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Penyelesaian pertidaksamaan 3 1 ​ lo g ( 3 x 2 + x ) < 3 1 ​ lo g ( 8 − x ) adalah ....

Penyelesaian pertidaksamaan adalah ....

  1. begin mathsize 14px style 4 over 3 end style < x < 8 atau x < -2

  2. 0 < x < 8 atau x < -2

  3. 0 < x < 8 atau -2 < x < begin mathsize 14px style negative 1 third end style

  4. x > 8 atau x < -2

  5. x > 8 atau -2 < x < begin mathsize 14px style negative 1 third end style

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

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Pembahasan

begin mathsize 14px style log presubscript straight space presuperscript 1 third end presuperscript space invisible function application open parentheses 3 straight x squared plus straight x close parentheses less than log presubscript straight space presuperscript 1 third end presuperscript space invisible function application open parentheses 8 minus straight x close parentheses  Pertama – tama space perhatikan space syarat space logaritma space colon  bold Syarat bold space bold space bold 1  3 straight x squared plus straight x greater than 0  straight x open parentheses 3 straight x plus 1 close parentheses greater than 0 end style

begin mathsize 14px style bold Syarat bold space bold 2  8 minus straight x greater than 0  minus straight x greater than negative 8  straight x less than 8    bold Pengerjaan bold space bold soal bold space bold colon  log presubscript straight space presuperscript 1 third end presuperscript invisible function application space open parentheses 3 straight x squared plus straight x close parentheses less than log presubscript straight space presuperscript 1 third end presuperscript invisible function application space open parentheses 8 minus straight x close parentheses  Karena space 0 less than 1 third less than 1 comma space maka  3 straight x squared plus straight x greater than 8 minus straight x  3 straight x squared plus 2 straight x minus 8 greater than 0  open parentheses 3 straight x minus 4 close parentheses open parentheses straight x plus 2 close parentheses greater than 0 end style

begin mathsize 14px style Dengan space mengiris space ketiga space daerah space arsiran space maka space didapat space colon  straight x less than negative 2 space atau space 4 over 3 less than straight x less than 8 end style

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