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Penyelesaian pertidaksamaan  adalah....

Penyelesaian pertidaksamaan begin mathsize 14px style square root of x minus 2 end root greater or equal than square root of x squared plus 2 x minus 8 end root comma space x element of straight real numbers end style adalah....undefined 

  1. begin mathsize 14px style x less or equal than negative 4 space atau space x greater or equal than 2 end style 

  2. size 14px x size 14px less or equal than size 14px minus size 14px 4 size 14px space size 14px atau size 14px space size 14px x size 14px greater or equal than size 14px minus size 14px 3 

  3. begin mathsize 14px style negative 3 less or equal than x less or equal than 2 end style 

  4. undefined 

  5. size 14px x size 14px greater or equal than size 14px minus size 14px 4 

Jawaban:

Kondisi jika ruas kanan dan kiri bernilai positif 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell square root of x minus 2 end root end cell greater or equal than cell square root of x squared plus 2 x minus 8 end root space space space kuadratkan space kedua space ruas end cell row cell straight x minus 2 space end cell greater or equal than cell straight x squared plus 2 straight x minus 8 end cell row 0 greater or equal than cell straight x squared plus straight x minus 6 end cell row 0 greater or equal than cell open parentheses straight x minus 2 close parentheses open parentheses straight x plus 3 close parentheses end cell end table end style 

Daerah penyelesaian (i)

 

Syarat dalam akar :

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell x minus 2 end cell greater or equal than 0 row x greater or equal than 2 row blank blank blank row cell x squared plus 2 x minus 8 end cell greater or equal than 0 row cell open parentheses x minus 2 close parentheses open parentheses x plus 4 close parentheses end cell greater or equal than 0 row blank blank blank end table end style 

Daerah penyelesaian syarat akar kedua :

Daerah penyelesaian gabungan :

Jadi jawaban yang tepat adalah B

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