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Pertanyaan

Pada segitiga A BC dengan A ( 1 , 1 , 1 ) , B ( 2 , − 1 , 3 ) , dan C ( 3 , 2 , − 1 ) , hasil dari ∣ ∣ ​ A B ∣ ∣ ​ A C + ∣ ∣ ​ A C ∣ ∣ ​ BC = ....

Pada segitiga  dengan , dan , hasil dari ....

  1. 9 i with rightwards arrow on top plus 12 j with rightwards arrow on top minus 18 k with rightwards arrow on top 

  2. 9 i with rightwards arrow on top minus 12 j with rightwards arrow on top plus 18 k with rightwards arrow on top 

  3. 12 i with rightwards arrow on top plus 9 j with rightwards arrow on top minus 18 k with rightwards arrow on top 

  4. 12 i with rightwards arrow on top minus 9 j with rightwards arrow on top plus 18 k with rightwards arrow on top 

  5. i with rightwards arrow on top plus j with rightwards arrow on top plus 2 k with rightwards arrow on top 

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N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

jawaban yang benar adalah A.

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Pembahasan

Pembahasan
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Menghitung vektor Menghitung panjang vektor Menghitung vektor Menghitung panjang vektor Menghitung vektor Menghitung Oleh karena itu, jawaban yang benar adalah A.

Menghitung vektor stack A B with rightwards arrow on top 

table attributes columnalign right center left columnspacing 0px end attributes row cell stack A B with rightwards arrow on top end cell equals cell B with rightwards arrow on top minus A with rightwards arrow on top end cell row blank equals cell open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses minus open parentheses table row 1 row 1 row 1 end table close parentheses end cell row blank equals cell open parentheses table row 1 row cell negative 2 end cell row 2 end table close parentheses end cell end table 

Menghitung panjang vektor open vertical bar stack A B with rightwards arrow on top close vertical bar

 table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar stack A B with rightwards arrow on top close vertical bar end cell equals cell square root of 1 squared plus open parentheses negative 2 close parentheses squared plus 2 squared end root end cell row blank equals cell square root of 1 plus 4 plus 4 end root end cell row blank equals cell square root of 9 end cell row blank equals 3 end table 

Menghitung vektor stack A C with rightwards arrow on top 

table attributes columnalign right center left columnspacing 0px end attributes row cell stack A C with rightwards arrow on top end cell equals cell C with rightwards arrow on top minus A with rightwards arrow on top end cell row blank equals cell open parentheses table row 3 row 2 row cell negative 1 end cell end table close parentheses minus open parentheses table row 1 row 1 row 1 end table close parentheses end cell row blank equals cell open parentheses table row 2 row 1 row cell negative 2 end cell end table close parentheses end cell end table 

Menghitung panjang vektor open vertical bar stack A C with rightwards arrow on top close vertical bar  

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar stack A C with rightwards arrow on top close vertical bar end cell equals cell square root of 2 squared plus 1 squared plus open parentheses negative 2 close parentheses squared end root end cell row blank equals cell square root of 4 plus 1 plus 4 end root end cell row blank equals cell square root of 9 end cell row blank equals 3 end table 

Menghitung vektor stack B C with rightwards arrow on top 

table attributes columnalign right center left columnspacing 0px end attributes row cell stack B C with rightwards arrow on top end cell equals cell C with rightwards arrow on top minus B with rightwards arrow on top end cell row blank equals cell open parentheses table row 3 row 2 row cell negative 1 end cell end table close parentheses minus open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses end cell row blank equals cell open parentheses table row 1 row 3 row cell negative 4 end cell end table close parentheses end cell end table 

Menghitung open vertical bar stack A B with rightwards arrow on top close vertical bar stack A C with rightwards arrow on top plus open vertical bar stack A C with rightwards arrow on top close vertical bar stack B C with rightwards arrow on top 

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar stack A B with rightwards arrow on top close vertical bar stack A C with rightwards arrow on top plus open vertical bar stack A C with rightwards arrow on top close vertical bar stack B C with rightwards arrow on top end cell equals cell 3 open parentheses table row 2 row 1 row cell negative 2 end cell end table close parentheses plus 3 open parentheses table row 1 row 3 row cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row 6 row 3 row cell negative 6 end cell end table close parentheses plus open parentheses table row 3 row 9 row cell negative 12 end cell end table close parentheses end cell row blank equals cell open parentheses table row 9 row 12 row cell negative 18 end cell end table close parentheses end cell row blank equals cell 9 i with rightwards arrow on top plus 12 j with rightwards arrow on top minus 18 k with rightwards arrow on top end cell end table 

Oleh karena itu, jawaban yang benar adalah A.

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Diketahui vektor p ⇀ ​ = 8 i − 2 j ​ + 5 k dan vektor q ⇀ ​ = 2 i + j ​ − k . Tentukan: 2 p ⇀ ​ − q ⇀ ​ 2 p ⇀ ​ + 3 q ⇀ ​

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