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Pertanyaan

Nilai x → 1 lim ​ x − 1 2 x 2 − 7 x + 5 ​ = ...

Nilai

  1. -5

  2. -3

  3. 4

  4. 5

  5. 10

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Master Teacher

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Pembahasan

Faktorkan pembilang Ingat konsep limit Sehingga

Faktorkan pembilang

limit as x rightwards arrow 1 of fraction numerator 2 x squared minus 7 x plus 5 over denominator x minus 1 end fraction equals limit as x rightwards arrow 1 of fraction numerator left parenthesis 2 x minus 5 right parenthesis left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis end fraction equals limit as x rightwards arrow 1 of 2 x minus 5

Ingat konsep limit

limit as x rightwards arrow a of f left parenthesis x right parenthesis equals f left parenthesis a right parenthesis

Sehingga

limit as x rightwards arrow 1 of 2 x minus 5 equals 2 left parenthesis 1 right parenthesis minus 5 equals negative 3

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