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Pertanyaan

Nilai x → 1 lim ​ x 2 − 2 x + 1 sin 2 ( x − 1 ) ​ = ....

Nilai

  1. 0

  2. 1

  3. 2

  4. 4

  5. infinity

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F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

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Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator sin squared left parenthesis x minus 1 right parenthesis over denominator x squared minus 2 x plus 1 end fraction end cell equals cell limit as x rightwards arrow 1 of fraction numerator sin squared left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis squared end fraction end cell row blank equals cell limit as x rightwards arrow 1 of open parentheses fraction numerator sin left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis end fraction close parentheses squared end cell row blank equals cell open parentheses limit as x rightwards arrow 1 of fraction numerator sin left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis end fraction close parentheses squared end cell row blank equals cell open parentheses 1 close parentheses squared end cell row blank equals 1 end table

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Nilai x → 3 π ​ lim ​ sin ( 3 x − π ) tan ( 3 x − π ) cos ( 2 x ) ​ adalah ...

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