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Hasil dari begin mathsize 14px style limit as x rightwards arrow 1 of invisible function application fraction numerator tan squared invisible function application open parentheses 3 x minus 3 close parentheses over denominator sin invisible function application open parentheses 4 x minus 4 close parentheses squared end fraction end style adalah ...

  1. size 14px minus size 14px 9 over size 14px 16     

  2. size 14px minus size 14px 3 over size 14px 4     

  3. undefined       

  4. size 14px 3 over size 14px 4     

  5. size 14px 9 over size 14px 16       

8 dari 10 siswa nilainya naik

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M. Robo

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepat adalah E.

Perhatikan bahwa

begin mathsize 14px style limit as x rightwards arrow 1 of invisible function application fraction numerator tan squared invisible function application open parentheses 3 x minus 3 close parentheses over denominator sin invisible function application open parentheses 4 x minus 4 close parentheses squared end fractionequals limit as x rightwards arrow 1 of invisible function application fraction numerator tan squared invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator sin invisible function application open parentheses 4 open parentheses x minus 1 close parentheses close parentheses squared end fractionequals limit as x rightwards arrow 1 of invisible function application fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses times tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fractionequals limit as x rightwards arrow 1 of invisible function application open parentheses fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses times tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fraction times open parentheses x minus 1 close parentheses squared over open parentheses x minus 1 close parentheses squared close parenthesesequals limit as x rightwards arrow 1 of invisible function application open parentheses fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator open parentheses x minus 1 close parentheses end fraction times fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator open parentheses x minus 1 close parentheses end fraction times fraction numerator open parentheses x minus 1 close parentheses squared over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fraction close parenthesesequals limit as x rightwards arrow 1 of invisible function application open parentheses fraction numerator 3 times 3 over denominator 16 end fraction times fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator 3 open parentheses x minus 1 close parentheses end fraction times fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator 3 open parentheses x minus 1 close parentheses end fraction times fraction numerator 16 open parentheses x minus 1 close parentheses squared over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fraction close parenthesesequals 9 over 16 times 1 times 1 times 1equals 9 over 16 end style  

Jadi, jawaban yang tepat adalah E.

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15

Alan Dwi Nugroho

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