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Pertanyaan

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Hasil dari begin mathsize 14px style limit as x rightwards arrow 1 of invisible function application fraction numerator tan squared invisible function application open parentheses 3 x minus 3 close parentheses over denominator sin invisible function application open parentheses 4 x minus 4 close parentheses squared end fraction end style adalah ...

  1. size 14px minus size 14px 9 over size 14px 16     

  2. size 14px minus size 14px 3 over size 14px 4     

  3. undefined       

  4. size 14px 3 over size 14px 4     

  5. size 14px 9 over size 14px 16       

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M. Robo

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

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Pembahasan

Perhatikan bahwa Jadi, jawaban yang tepat adalah E.

Perhatikan bahwa

begin mathsize 14px style limit as x rightwards arrow 1 of invisible function application fraction numerator tan squared invisible function application open parentheses 3 x minus 3 close parentheses over denominator sin invisible function application open parentheses 4 x minus 4 close parentheses squared end fractionequals limit as x rightwards arrow 1 of invisible function application fraction numerator tan squared invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator sin invisible function application open parentheses 4 open parentheses x minus 1 close parentheses close parentheses squared end fractionequals limit as x rightwards arrow 1 of invisible function application fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses times tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fractionequals limit as x rightwards arrow 1 of invisible function application open parentheses fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses times tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fraction times open parentheses x minus 1 close parentheses squared over open parentheses x minus 1 close parentheses squared close parenthesesequals limit as x rightwards arrow 1 of invisible function application open parentheses fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator open parentheses x minus 1 close parentheses end fraction times fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator open parentheses x minus 1 close parentheses end fraction times fraction numerator open parentheses x minus 1 close parentheses squared over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fraction close parenthesesequals limit as x rightwards arrow 1 of invisible function application open parentheses fraction numerator 3 times 3 over denominator 16 end fraction times fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator 3 open parentheses x minus 1 close parentheses end fraction times fraction numerator tan invisible function application open parentheses 3 open parentheses x minus 1 close parentheses close parentheses over denominator 3 open parentheses x minus 1 close parentheses end fraction times fraction numerator 16 open parentheses x minus 1 close parentheses squared over denominator sin invisible function application open parentheses 16 open parentheses x minus 1 close parentheses squared close parentheses end fraction close parenthesesequals 9 over 16 times 1 times 1 times 1equals 9 over 16 end style  

Jadi, jawaban yang tepat adalah E.

Perdalam pemahamanmu bersama Master Teacher
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3

Alan Dwi Nugroho

Pembahasan lengkap banget Mudah dimengerti

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