Nilai limx→0x3x2−x=...

Pertanyaan

Nilai $table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 0 of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 3 x squared minus x over denominator x end fraction end cell end table equals...$

H. Janatu

Master Teacher

Mahasiswa/Alumni Universitas Riau

Jawaban terverifikasi

Pembahasan

Jika hasil substitusi nilai x adalah bentuk tak tentu 0 over 0 , maka nilai limit dapat diselesaikan dengan pemfaktoran/kali sekawan (untuk bentuk akar).

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 0 of fraction numerator 3 x squared minus x over denominator x end fraction end cell equals cell fraction numerator 3 left parenthesis 0 right parenthesis squared minus 0 over denominator 0 end fraction equals 0 over 0 end cell row cell limit as x rightwards arrow 0 of fraction numerator 3 x squared minus x over denominator x end fraction end cell equals cell limit as x rightwards arrow 0 of fraction numerator up diagonal strike x open parentheses 3 x minus 1 close parentheses over denominator up diagonal strike x end fraction end cell row blank equals cell 3 left parenthesis 0 right parenthesis minus 1 end cell row blank equals cell negative 1 end cell end table$

Jadi, jawaban yang tepat adalah C.