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Pertanyaan

Nilai begin mathsize 14px style x end style yang memenuhi persamaan matriks open parentheses table row 1 2 row 4 3 end table close parentheses open parentheses table row cell negative 1 end cell 3 row 2 cell negative 5 end cell end table close parentheses equals open parentheses table row cell 2 x end cell cell 3 y end cell row cell negative 2 end cell z end table close parentheses plus open parentheses table row y cell 2 z end cell row 4 cell negative 4 end cell end table close parentheses adalah ....space 

  1. begin mathsize 14px style 6 end style 

  2. begin mathsize 14px style 3 end style 

  3. begin mathsize 14px style 1 end style 

  4. begin mathsize 14px style negative 2 end style 

  5. begin mathsize 14px style negative 3 end style 

I. Ridha

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.space 

Pembahasan

Ingat kembali:

  • open parentheses table row a b row c d end table close parentheses open parentheses table row m n row o p end table close parentheses equals open parentheses table row cell a open parentheses m close parentheses plus b open parentheses o close parentheses end cell cell a open parentheses n close parentheses plus b open parentheses p close parentheses end cell row cell c open parentheses m close parentheses plus d open parentheses o close parentheses end cell cell c open parentheses n close parentheses plus d open parentheses p close parentheses end cell end table close parentheses
  • open parentheses table row a b row c d end table close parentheses plus open parentheses table row m n row o p end table close parentheses equals open parentheses table row cell a plus m end cell cell b plus n end cell row cell c plus o end cell cell d plus p end cell end table close parentheses
  • Jika open parentheses table row a b row c d end table close parentheses equals open parentheses table row m n row o p end table close parentheses, maka a equals mb equals nc equals o, dan d equals p.

Dengan demikian, diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row 1 2 row 4 3 end table close parentheses open parentheses table row cell negative 1 end cell 3 row 2 cell negative 5 end cell end table close parentheses end cell equals cell open parentheses table row cell 1 open parentheses negative 1 close parentheses plus 2 open parentheses 2 close parentheses end cell cell 1 open parentheses 3 close parentheses plus 2 open parentheses negative 5 close parentheses end cell row cell 4 open parentheses negative 1 close parentheses plus 3 open parentheses 2 close parentheses end cell cell 4 open parentheses 3 close parentheses plus 3 open parentheses negative 5 close parentheses end cell end table close parentheses end cell row blank equals cell open parentheses table row cell open parentheses negative 1 close parentheses plus 4 end cell cell 3 plus open parentheses negative 10 close parentheses end cell row cell open parentheses negative 4 close parentheses plus 6 end cell cell 12 plus open parentheses negative 15 close parentheses end cell end table close parentheses end cell row blank equals cell open parentheses table row 3 cell negative 7 end cell row 2 cell negative 3 end cell end table close parentheses end cell end table

dan

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row cell 2 x end cell cell 3 y end cell row cell negative 2 end cell z end table close parentheses plus open parentheses table row y cell 2 z end cell row 4 cell negative 4 end cell end table close parentheses end cell equals cell open parentheses table row cell 2 x plus y end cell cell 3 y plus 2 z end cell row cell negative 2 plus 4 end cell cell z plus open parentheses negative 4 close parentheses end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 2 x plus y end cell cell 3 y plus 2 z end cell row 2 cell z minus 4 end cell end table close parentheses end cell end table

sehingga

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row 1 2 row 4 3 end table close parentheses open parentheses table row cell negative 1 end cell 3 row 2 cell negative 5 end cell end table close parentheses end cell equals cell open parentheses table row cell 2 x end cell cell 3 y end cell row cell negative 2 end cell z end table close parentheses plus open parentheses table row y cell 2 z end cell row 4 cell negative 4 end cell end table close parentheses end cell row cell open parentheses table row 3 cell negative 7 end cell row 2 cell negative 3 end cell end table close parentheses end cell equals cell open parentheses table row cell 2 x plus y end cell cell 3 y plus 2 z end cell row 2 cell z minus 4 end cell end table close parentheses end cell end table

sehingga diperoleh:

table row cell 2 x plus y equals 3 end cell blank cell midline horizontal ellipsis open parentheses 1 close parentheses end cell row cell 3 y plus 2 z equals negative 7 end cell blank cell midline horizontal ellipsis open parentheses 2 close parentheses end cell row cell z minus 4 equals negative 3 end cell blank cell midline horizontal ellipsis open parentheses 3 close parentheses end cell end table

Dari open parentheses 3 close parentheses, diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell z minus 4 end cell equals cell negative 3 end cell row z equals cell negative 3 plus 4 end cell row z equals 1 end table

Dengan menyubtitusi z equals 1 ke open parentheses 2 close parentheses, diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell 3 y plus 2 open parentheses 1 close parentheses end cell equals cell negative 7 end cell row cell 3 y plus 2 end cell equals cell negative 7 end cell row cell 3 y end cell equals cell negative 7 minus 2 end cell row cell 3 y end cell equals cell negative 9 end cell row y equals cell fraction numerator negative 9 over denominator 3 end fraction end cell row y equals cell negative 3 end cell end table

Dengan menyubtitusi y equals negative 3 ke open parentheses 1 close parentheses, diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 x plus y end cell equals 3 row cell 2 x plus open parentheses negative 3 close parentheses end cell equals 3 row cell 2 x minus 3 end cell equals 3 row cell 2 x end cell equals cell 3 plus 3 end cell row cell 2 x end cell equals 6 row x equals cell 6 over 2 end cell row x equals 3 end table

Jadi, nilai begin mathsize 14px style x end style yang memenuhi persamaan matriks open parentheses table row 1 2 row 4 3 end table close parentheses open parentheses table row cell negative 1 end cell 3 row 2 cell negative 5 end cell end table close parentheses equals open parentheses table row cell 2 x end cell cell 3 y end cell row cell negative 2 end cell z end table close parentheses plus open parentheses table row y cell 2 z end cell row 4 cell negative 4 end cell end table close parentheses adalah 3.

Oleh karena itu, jawaban yang benar adalah B.space 

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