Roboguru

Nilai  yang memenuhi persamaan eksponensial  adalah ....

Pertanyaan

Nilai x yang memenuhi persamaan eksponensial open parentheses 1 fourth close parentheses to the power of x minus 16 cross times 2 to the power of x equals 0 adalah ....

  1. negative 4 over 3 

  2. negative 3 over 4 

  3. negative 1 third 

  4. 3 over 4 

  5. 4 over 3 

Pembahasan Soal:

Ingat kembali bentuk persamaan eksponen berikut:

straight a to the power of straight f open parentheses straight x close parentheses end exponent equals straight a to the power of straight m comma space straight a greater than 0 space dan space straight a not equal to 1 rightwards arrow space straight f open parentheses straight x close parentheses equals straight g open parentheses straight x close parentheses 

Maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 1 fourth close parentheses to the power of x minus 16 cross times 2 to the power of x end cell equals 0 row cell open parentheses 1 fourth close parentheses to the power of x end cell equals cell 16 cross times 2 to the power of x end cell row cell open parentheses 1 over 2 squared close parentheses to the power of x end cell equals cell 2 to the power of 4 cross times 2 to the power of x end cell row cell open parentheses 2 to the power of negative 2 end exponent close parentheses to the power of x end cell equals cell 2 to the power of 4 plus x end exponent end cell row cell 2 to the power of negative 2 x end exponent end cell equals cell 2 to the power of 4 plus x end exponent end cell row cell negative 2 x end cell equals cell 4 plus x end cell row cell negative 2 x minus x end cell equals 4 row cell negative 3 x end cell equals 4 row x equals cell negative 4 over 3 end cell end table  

Jadi, jawaban yang benar adalah A.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 19 Juli 2021

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