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Jika (251​)x−1=5352x+1​ maka x=….

Pertanyaan

Jika open parentheses 1 over 25 close parentheses to the power of x minus 1 end exponent equals 5 cube root of 5 to the power of 2 x plus 1 end exponent end root maka x equals horizontal ellipsis

  1. 0 comma 25 

  2. 0 comma 5 

  3. 1 

  4. 2 

  5. 4

I. Ridha

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.space 

Pembahasan

Ingat kembali:

  • Jika a to the power of f open parentheses x close parentheses end exponent equals a to the power of g open parentheses x close parentheses end exponenta greater than 0, dan a not equal to 1, maka f open parentheses x close parentheses equals g open parentheses x close parentheses
  • 1 over a to the power of m equals a to the power of negative m end exponent dengan a not equal to 0
  • n-th root of a to the power of m end root equals a to the power of m over n end exponent dengan a greater than 0
  • a equals a to the power of 1
  • a to the power of m a to the power of n equals a to the power of m plus n end exponent
  • open parentheses a to the power of m close parentheses to the power of n equals a to the power of m n end exponent

Dengan demikian, 

open parentheses 1 over 25 close parentheses to the power of x minus 1 end exponent equals 5 cube root of 5 to the power of 2 x plus 1 end exponent end root open parentheses 1 over 5 squared close parentheses to the power of x minus 1 end exponent equals 5 to the power of 1 open parentheses 5 to the power of fraction numerator 2 x plus 1 over denominator 3 end fraction end exponent close parentheses open parentheses 5 to the power of negative 2 end exponent close parentheses to the power of x minus 1 end exponent equals 5 to the power of 1 open parentheses 5 to the power of fraction numerator 2 x plus 1 over denominator 3 end fraction end exponent close parentheses 5 to the power of negative 2 x plus 2 end exponent equals 5 to the power of 1 plus fraction numerator 2 x plus 1 over denominator 3 end fraction end exponent 5 to the power of negative 2 x plus 2 end exponent equals 5 to the power of 3 over 3 plus fraction numerator 2 x plus 1 over denominator 3 end fraction end exponent 5 to the power of negative 2 x plus 2 end exponent equals 5 to the power of fraction numerator 2 x plus 1 plus 3 over denominator 3 end fraction end exponent 5 to the power of negative 2 x plus 2 end exponent equals 5 to the power of fraction numerator 2 x plus 4 over denominator 3 end fraction end exponent

sehingga karena a equals 5 yang berarti a greater than 0, dan a not equal to 1, maka diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell table row cell negative 2 x plus 2 equals fraction numerator 2 x plus 4 over denominator 3 end fraction end cell row cell open parentheses negative 2 x plus 2 close parentheses cross times 3 equals 2 x plus 4 end cell row cell negative 6 x plus 6 equals 2 x plus 4 end cell row cell negative 6 x equals 2 x plus 4 minus 6 end cell row cell negative 6 x minus 2 x equals 4 minus 6 end cell row cell negative 8 x equals negative 2 end cell row cell x equals fraction numerator negative 2 over denominator negative 8 end fraction end cell row cell x equals fraction numerator negative 2 divided by negative 2 over denominator negative 8 divided by negative 2 end fraction end cell row cell x equals 1 fourth end cell row cell x equals 0 comma 25 end cell end table end cell end table

Oleh karena itu, jawaban yang benar adalah A.space 

201

5.0 (4 rating)

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