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Nilai limit berikut adalah...

Pertanyaan

Nilai limit berikut adalah...

begin mathsize 14px style stack L i m with x rightwards arrow 3 below fraction numerator 3 x squared minus 5 x minus 12 over denominator x squared minus 9 end fraction equals... end style

  1. ...space space space 

  2. ...space space space 

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell stack L i m with x rightwards arrow 3 below fraction numerator 3 x squared minus 5 x minus 12 over denominator x squared minus 9 end fraction end cell equals cell stack L i m with x rightwards arrow 3 below fraction numerator open parentheses 3 x plus 4 close parentheses open parentheses x minus 3 close parentheses over denominator left parenthesis x plus 3 right parenthesis left parenthesis x minus 3 right parenthesis end fraction end cell row blank equals cell stack L i m with x rightwards arrow 3 below fraction numerator 3 x plus 4 over denominator x plus 3 end fraction end cell row blank equals cell fraction numerator 3 left parenthesis 3 right parenthesis plus 4 over denominator 3 plus 3 end fraction end cell row blank equals cell 13 over 6 end cell end table end style

Jadi,  nilai dari begin mathsize 14px style stack L i m with x rightwards arrow 3 below fraction numerator 3 x squared minus 5 x minus 12 over denominator x squared minus 9 end fraction end style adalah begin mathsize 14px style 13 over 6 end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 12 April 2021

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