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Pertanyaan

Nilai dari x → 1 lim ​ x 2 + 3 ​ − 2 x − 1 ​ = …

Nilai dari  

  1. begin mathsize 14px style negative 2 end style 

  2. undefined 

  3. begin mathsize 14px style 2 end style 

  4. begin mathsize 14px style 3 end style 

  5. begin mathsize 14px style 4 end style 

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R. Septa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.

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Pembahasan

Jadi, jawaban yang tepat adalah C.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator x minus 1 over denominator square root of x squared plus 3 end root minus 2 end fraction end cell equals cell limit as x rightwards arrow 1 of fraction numerator x minus 1 over denominator square root of x squared plus 3 end root minus 2 end fraction cross times fraction numerator square root of x squared plus 3 end root plus 2 over denominator square root of x squared plus 3 end root plus 2 end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator open parentheses x minus 1 close parentheses open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator open parentheses x squared plus 3 close parentheses minus 4 end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis x minus 1 right parenthesis open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator x squared minus 1 end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis x minus 1 right parenthesis open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator open parentheses x minus 1 close parentheses open parentheses x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator up diagonal strike left parenthesis x minus 1 right parenthesis end strike open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator up diagonal strike open parentheses x minus 1 close parentheses end strike open parentheses x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator square root of x squared plus 3 end root plus 2 over denominator x plus 1 end fraction end cell row blank equals cell fraction numerator square root of 1 squared plus 3 end root plus 2 over denominator 1 plus 1 end fraction end cell row blank equals cell fraction numerator 2 plus 2 over denominator 2 end fraction end cell row blank equals 2 row blank blank blank end table end style  

Jadi, jawaban yang tepat adalah C.

Latihan Bab

Konsep Kilat

Konsep Limit

Sifat Limit

Limit Fungsi Aljabar

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