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Pertanyaan

Nilai dari x → 1 lim ​ x 2 + 3 ​ − 2 x − 1 ​ = …

Nilai dari  

  1. begin mathsize 14px style negative 2 end style 

  2. undefined 

  3. begin mathsize 14px style 2 end style 

  4. begin mathsize 14px style 3 end style 

  5. begin mathsize 14px style 4 end style 

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R. Septa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.

Pembahasan

Jadi, jawaban yang tepat adalah C.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 of fraction numerator x minus 1 over denominator square root of x squared plus 3 end root minus 2 end fraction end cell equals cell limit as x rightwards arrow 1 of fraction numerator x minus 1 over denominator square root of x squared plus 3 end root minus 2 end fraction cross times fraction numerator square root of x squared plus 3 end root plus 2 over denominator square root of x squared plus 3 end root plus 2 end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator open parentheses x minus 1 close parentheses open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator open parentheses x squared plus 3 close parentheses minus 4 end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis x minus 1 right parenthesis open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator x squared minus 1 end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator left parenthesis x minus 1 right parenthesis open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator open parentheses x minus 1 close parentheses open parentheses x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator up diagonal strike left parenthesis x minus 1 right parenthesis end strike open parentheses square root of x squared plus 3 end root plus 2 close parentheses over denominator up diagonal strike open parentheses x minus 1 close parentheses end strike open parentheses x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 1 of fraction numerator square root of x squared plus 3 end root plus 2 over denominator x plus 1 end fraction end cell row blank equals cell fraction numerator square root of 1 squared plus 3 end root plus 2 over denominator 1 plus 1 end fraction end cell row blank equals cell fraction numerator 2 plus 2 over denominator 2 end fraction end cell row blank equals 2 row blank blank blank end table end style  

Jadi, jawaban yang tepat adalah C.

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Pertanyaan serupa

Tentukan nilai limit fungsi berikut! x → 2 lim ​ x 2 + x − 6 5 x − 6 ​ − x ​

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Jawaban terverifikasi

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