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Nilai a + b agar fungsi di bawah ini kontinu di x = − 1 dan x = 1 adalah ….

Nilai  agar fungsi di bawah ini kontinu di x =  dan x = adalah ….

begin mathsize 14px style f open parentheses x close parentheses equals open curly brackets table row cell 3 x plus a blank text Jika  end text blank x greater or equal than 1 end cell row cell 2 a x plus b blank text Jika end text blank minus 1 less than x less than 1 end cell row cell x plus a blank text Jika end text blank x less or equal than negative 1 end cell end table close end style

  1. 1begin mathsize 14px style space end style

  2. 2begin mathsize 14px style space end style

  3. 3begin mathsize 14px style space end style

  4. 6begin mathsize 14px style space end style

  5. 8begin mathsize 14px style space end style

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Pembahasan

Ingat bahwa limit dikatakan kontinu jika Maka, Jika f(x) akan kontinu x = sehingga, Kemudian, jika f(x) akan kontinu x = sehingga, Substitusi persamaan (2) ke persamaan (1) maka diperoleh: Maka . Jadi . Maka, jawaban yang tepat adalah C.

Ingat bahwa limit dikatakan kontinu jika

begin mathsize 14px style bold lim with bold x bold rightwards arrow bold a to the power of bold minus below bold invisible function application bold f bold left parenthesis bold x bold right parenthesis bold equals bold lim with bold x bold rightwards arrow bold a to the power of bold plus below bold invisible function application bold f bold left parenthesis bold x bold right parenthesis end style

Maka,

begin mathsize 14px style f open parentheses x close parentheses equals open curly brackets table row cell 3 x plus a blank text Jika  end text blank x greater or equal than 1 end cell row cell 2 a x plus b blank text Jika end text blank minus 1 less than x less than 1 end cell row cell x plus a blank text Jika end text blank x less or equal than negative 1 end cell end table close end style

Jika f(x) akan kontinu  x = begin mathsize 14px style 1 end style sehingga,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 1 to the power of minus of invisible function application 2 a x plus b end cell equals cell limit as x rightwards arrow 1 to the power of plus of invisible function application 3 x plus a end cell row cell 2 a left parenthesis 1 right parenthesis plus b end cell equals cell 3 left parenthesis 1 right parenthesis plus a space end cell row cell 2 a minus a plus b end cell equals 3 row cell space a plus b end cell equals cell 3 space horizontal ellipsis space space space left parenthesis 1 right parenthesis end cell end table end style 

Kemudian, jika f(x) akan kontinu x = begin mathsize 14px style negative 1 end style sehingga,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow negative 1 to the power of minus of invisible function application x plus 1 end cell equals cell limit as x rightwards arrow negative 1 to the power of plus of invisible function application 2 a x plus b end cell row cell left parenthesis negative 1 right parenthesis plus 1 end cell equals cell 2 a left parenthesis negative 1 right parenthesis plus b space end cell row cell negative 2 a plus b end cell equals cell 0 space end cell row b equals cell 2 a space horizontal ellipsis space space space left parenthesis 2 right parenthesis end cell end table end style 

Substitusi persamaan (2) ke persamaan (1) maka diperoleh:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell a plus 2 a end cell equals cell 3 space end cell row cell 3 a end cell equals cell 3 space end cell row a equals 1 end table end style  

Maka begin mathsize 14px style b equals 2 open parentheses 1 close parentheses equals 2 end style.

Jadi begin mathsize 14px style a plus b equals 1 plus 2 equals 3 end style.

Maka, jawaban yang tepat adalah C.

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