Pertanyaan

Nilai x → − 2 lim ( 2 x + 4 3 − 2 x 2 − 8 2 x − 8 ) adalah...

Nilai $x \to - 2 lim (\frac{3}{2 x + 4} - \frac{2 x - 8}{2 x ^{2} - 8})$ adalah...

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Habis dalam

Klaim

E. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

Pembahasan

Jadi, jawaban yang benar adalah A.

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow negative 2 of open parentheses table row cell fraction numerator 3 over denominator 2 x plus 4 end fraction minus fraction numerator 2 x minus 8 over denominator 2 x squared minus 8 end fraction end cell end table close parentheses end cell row blank equals cell limit as x rightwards arrow negative 2 of open parentheses table row cell fraction numerator 3 over denominator 2 x plus 4 end fraction minus fraction numerator 2 x minus 8 over denominator left parenthesis 2 x plus 4 right parenthesis left parenthesis x minus 2 right parenthesis end fraction end cell end table close parentheses end cell row blank equals cell limit as x rightwards arrow negative 2 of open parentheses table row cell fraction numerator 3 left parenthesis x minus 2 right parenthesis over denominator left parenthesis 2 x plus 4 right parenthesis left parenthesis x minus 2 right parenthesis end fraction minus fraction numerator 2 x minus 8 over denominator left parenthesis 2 x plus 4 right parenthesis left parenthesis x minus 2 right parenthesis end fraction end cell end table close parentheses end cell row blank equals cell limit as x rightwards arrow negative 2 of space open parentheses table row cell fraction numerator 3 x minus 6 minus left parenthesis 2 x minus 8 right parenthesis over denominator left parenthesis 2 x plus 4 right parenthesis left parenthesis x minus 2 right parenthesis end fraction end cell end table close parentheses end cell row blank equals cell limit as x rightwards arrow negative 2 of space open parentheses table row cell fraction numerator 3 x minus 6 minus 2 x plus 8 over denominator left parenthesis 2 x plus 4 right parenthesis left parenthesis x minus 2 right parenthesis end fraction end cell end table close parentheses end cell row blank equals cell limit as x rightwards arrow negative 2 of space open parentheses table row cell fraction numerator x plus 2 over denominator left parenthesis 2 x plus 4 right parenthesis left parenthesis x minus 2 right parenthesis end fraction end cell end table close parentheses end cell row blank equals cell limit as x rightwards arrow negative 2 of space open parentheses table row cell fraction numerator x plus 2 over denominator 2 left parenthesis x plus 2 right parenthesis left parenthesis x minus 2 right parenthesis end fraction end cell end table close parentheses end cell row blank equals cell limit as x rightwards arrow negative 2 of space open parentheses table row cell fraction numerator 1 over denominator 2 left parenthesis x minus 2 right parenthesis end fraction end cell end table close parentheses end cell row blank equals cell fraction numerator 1 over denominator 2 left parenthesis negative 2 minus 2 right parenthesis end fraction end cell row blank equals cell fraction numerator 1 over denominator 2 left parenthesis negative 4 right parenthesis end fraction end cell row blank equals cell negative 1 over 8 end cell end table$

Jadi, jawaban yang benar adalah A.