Roboguru

Natrium sianida dapat dibuat dengan mencampurkan sebanyak 50 mL larutan NaOH 0,1 M dengan 50 mL larutan asam sianida 0,1 M menurut reaksi: HCN + NaOH → NaCN + jika harga , senyawa tersebut dalam air

Natrium sianida dapat dibuat dengan mencampurkan sebanyak 50 mL larutan NaOH 0,1 M dengan 50 mL larutan asam sianida 0,1 M menurut reaksi: HCN + NaOH → NaCN + begin mathsize 14px style H subscript 2 O end style jika harga begin mathsize 14px style K subscript a space H C N equals 5 cross times 10 to the power of negative sign 10 end exponent end style, senyawa tersebut dalam air akan terhidrolisis dengan pH larutan ....

Jawaban:

begin mathsize 14px style n subscript NaOH equals 0 comma 1 cross times 50 equals 5 space mmol n subscript HCN equals 0 comma 1 cross times 50 equals 5 space mmol H C N open parentheses aq close parentheses and Na O H open parentheses aq close parentheses yields Na C N open parentheses aq close parentheses and H subscript 2 O open parentheses l close parentheses 5 space space space space space space space space space space space space space space space space 5 bottom enclose negative sign 5 space space space space space space space space space space space space minus sign 5 space space space space space space space space space space space space space space space space space plus 5 space space space space space space space space space space space space space plus 5 end enclose 0 space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space 5 space space space space space space space space space space space space space space space space space space 5  open square brackets C N to the power of minus sign close square brackets equals bevelled 5 over 100 equals 5 cross times 10 to the power of negative sign 2 end exponent space M C N to the power of minus sign open parentheses aq close parentheses and H subscript 2 O open parentheses l close parentheses equilibrium H C N open parentheses aq close parentheses and O H to the power of minus sign open parentheses aq close parentheses open square brackets O H to the power of minus sign close square brackets equals square root of K subscript w over K subscript a cross times open square brackets C N to the power of minus sign close square brackets end root open square brackets O H to the power of minus sign close square brackets equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 5 cross times 10 to the power of negative sign 10 end exponent end fraction cross times 5 cross times 10 to the power of negative sign 2 end exponent end root open square brackets O H to the power of minus sign close square brackets equals 10 to the power of negative sign 3 end exponent pOH equals minus sign log open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log open parentheses 10 to the power of negative sign 3 end exponent close parentheses pOH equals 3  pH equals 14 minus sign pOH pH equals 11 end style

Dengan demikian, maka jawaban yang tepat adalah 11.

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