Iklan

Pertanyaan

Jika ( x , y , z) merupakan penyelesaian SPLTV, nilai x + y + z = … .

Jika ( x,y,z) merupakan penyelesaian SPLTV,

begin mathsize 14px style open curly brackets table row cell 2 x and y equals 11 end cell row cell 3 y bond z equals 5 end cell row cell x and 2 z equals 1 end cell end table close end style 

nilai = … .

  1. -4

  2. -2

  3. 0

  4. 2

  5. 4

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

01

:

09

:

43

:

19

Klaim

Iklan

M. Robo

Master Teacher

Jawaban terverifikasi

Jawaban

x + y + z = 5 + 1 - 2 = 4 .

= 5 + 1 - 2 = 4.

Pembahasan

2 x + y = 11 ……… ( 1) 3 y - z = 5 ……… ( 2) x + 2 z = 1 ……… ( 3) Eliminasi y melalui persamaan (1) dan (2) Eliminasi z melalui persamaan (3) dan (4) Substitusi x ke persamaan (3) sehingga Substitusi z ke persamaan (2) sehingga Jadi, x + y + z = 5 + 1 - 2 = 4 .

2= 11 ……… (1)

3= 5 ……… (2)

+ 2= 1 ……… (3)

 

Eliminasi y melalui persamaan (1) dan (2)

begin mathsize 14px style table row cell 2 x and y equals 11 end cell row cell 3 y bond z equals 5 end cell end table space space space space space space space open vertical bar table row cell cross times 3 end cell row cell cross times 1 end cell end table close vertical bar space table row cell 6 x plus up diagonal strike 3 y end strike equals 33 space space end cell row cell bottom enclose up diagonal strike 3 y end strike minus sign z equals 5 space space space space minus sign end enclose end cell end table space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 6 x and z equals 28 space......... space left parenthesis 4 right parenthesis end style   

 

Eliminasi melalui persamaan (3) dan (4)

begin mathsize 14px style table row cell x and 2 z equals 1 end cell row cell 6 x and z equals 28 end cell end table space space space space space space space open vertical bar table row cell cross times 1 end cell row cell cross times 2 end cell end table close vertical bar space table row cell x plus up diagonal strike 2 z end strike equals 1 space space end cell row cell bottom enclose 12 x plus space up diagonal strike 2 z end strike equals 56 space space space space minus sign end enclose end cell end table space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space minus sign 11 x equals minus sign 55 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space x equals fraction numerator negative sign 55 over denominator negative sign 11 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space x equals 5 end style  

 

Substitusi x ke persamaan (3) sehingga

begin mathsize 14px style x and 2 z equals 1 5 plus 2 z equals 1 2 z equals 1 minus sign 5 z equals fraction numerator negative sign 4 over denominator 2 end fraction z equals minus sign 2 end style  

 

Substitusi z ke persamaan (2) sehingga

begin mathsize 14px style 3 y bond z equals 5 3 y minus sign open parentheses negative sign 2 close parentheses equals 5 3 y plus 2 equals 5 3 y equals 5 minus sign 2 y equals 3 over 3 y equals 1 end style 

 

Jadi, = 5 + 1 - 2 = 4.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

2

Iklan

Pertanyaan serupa

Diberikan sistem persamaan linier tiga variabel seperti berikut. ⎩ ⎨ ⎧ ​ 2 x + 5 y + 3 z = 9 4 x + 10 y + 6 z = 18 6 x + 15 y + 9 z = 27 ​ Salah satu penyelesaian dari sistem persamaan di atas y...

3

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2025 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia