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Jika vektor a = − 4 i ​ + 3 j ​ − 4 k , b = − i ​ + j ​ + 3 k dan c = 4 i − j ​ + 4 k , proyeksi orthogonal vektor a pada ( b − c ⇀ ) adalah ...

Jika vektor  dan , proyeksi orthogonal vektor  pada  adalah ...

  1. begin mathsize 14px style stack negative 5 i with rightwards arrow on top plus stack 2 j with rightwards arrow on top minus k with rightwards arrow on top end style 

  2. begin mathsize 14px style stack negative 4 i with rightwards arrow on top plus stack 4 j with rightwards arrow on top minus stack 2 k with rightwards arrow on top end style 

  3. begin mathsize 14px style stack 2 i with rightwards arrow on top minus stack 2 j with rightwards arrow on top plus k with rightwards arrow on top end style 

  4. begin mathsize 14px style stack 4 i with rightwards arrow on top minus stack 4 j with rightwards arrow on top plus stack 2 k with rightwards arrow on top end style 

  5. begin mathsize 14px style stack 6 i with rightwards arrow on top minus stack 6 j with rightwards arrow on top plus stack 3 k with rightwards arrow on top end style 

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Proyeksi ortogonal adalah gambar proyeksi yang bidang proyeksinya mempunyai sudut tegak lurus terhadap proyektornya. Diketahui: Vektor : Proyeksi orthogonal vektor pada adalah sebagai berikut: Sehingga,proyeksi orthogonal vektor pada adalah . Jadi, jawaban yang tepat adalah A.

Proyeksi ortogonal adalah gambar proyeksi yang bidang proyeksinya mempunyai sudut tegak lurus terhadap proyektornya.

Diketahui:

begin mathsize 14px style a with rightwards arrow on top equals stack negative 4 i with rightwards arrow on top plus stack 3 j with rightwards arrow on top minus stack 4 k with rightwards arrow on top b with rightwards arrow on top equals stack negative i with rightwards arrow on top plus j with rightwards arrow on top plus stack 3 k with rightwards arrow on top c with rightwards arrow on top equals stack 4 i with rightwards arrow on top minus j with rightwards arrow on top plus stack 4 k with rightwards arrow on top end style 

 Vektor begin mathsize 14px style open parentheses b with rightwards arrow on top minus c with rightwards harpoon with barb upwards on top close parentheses end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses b with rightwards arrow on top minus c with rightwards arrow on top close parentheses end cell equals cell stack negative i with rightwards arrow on top plus j with rightwards arrow on top plus stack 3 k with rightwards arrow on top minus open parentheses stack 4 i with rightwards arrow on top minus j with rightwards arrow on top plus stack 4 k with rightwards arrow on top close parentheses end cell row blank equals cell stack negative 5 i with rightwards arrow on top plus stack 2 j with rightwards arrow on top minus k with rightwards arrow on top end cell end table end style 

Proyeksi orthogonal vektor begin mathsize 14px style a with rightwards arrow on top end style pada begin mathsize 14px style open parentheses b with rightwards arrow on top minus c with rightwards harpoon with barb upwards on top close parentheses end style adalah sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell proyeksi space vektor end cell equals cell open parentheses fraction numerator a with rightwards arrow on top times open parentheses b with rightwards arrow on top minus c with rightwards arrow on top close parentheses over denominator open vertical bar stack b with rightwards arrow on top minus c with rightwards arrow on top with rightwards arrow on top close vertical bar squared end fraction close parentheses open parentheses b with rightwards arrow on top minus c with rightwards arrow on top close parentheses end cell row blank equals cell open parentheses fraction numerator negative 4 left parenthesis negative 5 right parenthesis plus 3 left parenthesis 2 right parenthesis plus left parenthesis negative 4 right parenthesis left parenthesis negative 1 right parenthesis over denominator open parentheses square root of left parenthesis negative 5 right parenthesis squared plus 2 squared plus left parenthesis negative 1 right parenthesis squared end root close parentheses squared end fraction close parentheses open parentheses stack negative 5 j with rightwards arrow on top plus stack 2 j with rightwards arrow on top minus k with rightwards arrow on top close parentheses end cell row blank equals cell open parentheses fraction numerator 20 plus 6 plus 4 over denominator open parentheses square root of 25 plus 4 plus 1 end root close parentheses squared end fraction close parentheses open parentheses stack negative 5 j with rightwards arrow on top plus stack 2 j with rightwards arrow on top minus k with rightwards arrow on top close parentheses end cell row blank equals cell open parentheses 30 over 30 close parentheses open parentheses stack negative 5 j with rightwards arrow on top plus stack 2 j with rightwards arrow on top minus k with rightwards arrow on top close parentheses end cell row blank equals cell stack negative 5 j with rightwards arrow on top plus stack 2 j with rightwards arrow on top minus k with rightwards arrow on top end cell end table end style 

Sehingga, proyeksi orthogonal vektor begin mathsize 14px style a with rightwards arrow on top end style pada begin mathsize 14px style open parentheses b with rightwards arrow on top minus c with rightwards harpoon with barb upwards on top close parentheses end style adalah begin mathsize 14px style stack negative 5 i with rightwards arrow on top plus stack 2 j with rightwards arrow on top minus k with rightwards arrow on top end style.

Jadi, jawaban yang tepat adalah A.

 

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Diketahui vektor a = ⎝ ⎛ ​ − 1 − 3 2 ​ ⎠ ⎞ ​ dan b = ⎝ ⎛ ​ − 2 6 1 ​ ⎠ ⎞ ​ . Vektor proyeksi ortogonal dari vektor b pada vektor a adalah ....

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