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Pertanyaan

Jika x → 0 lim ​ sin 6 x x a sin 4 x ​ = 1 , nilai yang memenuhi ....

Jika , nilai a yang memenuhi ....

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A. Azriah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

jawaban yang benar adalah B.

Pembahasan

Ingat sifat-sifat limit trigonometri berikut! x → c lim ​ k=k Penyelesaian: Kalikan kedua ruas dengan x 6 x 6 ​ untuk mengubah bentuk trigonometri agar sesuai dengan sifat-sifat trigonometri. maka diperoleh: x 2 x a ​ x a − 2 x a − 2 a − 2 a ​ = = = = = ​ 1 1 x 0 0 2 ​ Oleh karena itu, jawaban yang benar adalah B.

Ingat sifat-sifat limit trigonometri berikut!

  1. stack text lim end text with x rightwards arrow 0 below fraction numerator text sin  end text x over denominator x end fraction equals 1 
  2.  stack text lim end text with x rightwards arrow 0 below blank fraction numerator x over denominator text sin end text space x end fraction equals 1

Penyelesaian:
Kalikan kedua ruas dengan  untuk mengubah bentuk trigonometri agar sesuai dengan sifat-sifat trigonometri.

table attributes columnalign right center left columnspacing 0px end attributes row cell stack text lim end text with x rightwards arrow 0 below fraction numerator x to the power of a space sin to the power of 4 space x over denominator sin to the power of 6 space x end fraction end cell equals 1 row cell stack text lim end text with x rightwards arrow 0 below open parentheses fraction numerator x to the power of a space sin to the power of 4 space x over denominator sin to the power of 6 space x end fraction times x to the power of 6 over x to the power of 6 close parentheses end cell equals cell 1. blank bold x to the power of bold 6 over bold x to the power of bold 6 end cell row cell limit as straight x rightwards arrow 0 of open parentheses fraction numerator straight x to the power of straight a space sin to the power of 4 space straight x over denominator straight x to the power of 6 end fraction times blank fraction numerator straight x to the power of 6 over denominator sin to the power of 6 space straight x end fraction close parentheses end cell equals cell 1. blank left parenthesis 1 right parenthesis end cell row cell limit as straight x rightwards arrow 0 of open parentheses fraction numerator straight x to the power of straight a space sin to the power of 4 space straight x over denominator straight x squared. straight x to the power of 4 end fraction times blank fraction numerator straight x to the power of 6 over denominator sin to the power of 6 space straight x end fraction close parentheses end cell equals 1 row cell limit as straight x rightwards arrow 0 of open parentheses straight x to the power of straight a over straight x squared times fraction numerator sin to the power of 4 space straight x over denominator straight x to the power of 4 end fraction times blank fraction numerator straight x to the power of 6 over denominator sin to the power of 6 space straight x end fraction close parentheses end cell equals 1 row cell limit as straight x rightwards arrow 0 of blank straight x to the power of straight a over straight x squared times limit as straight x rightwards arrow 0 of blank fraction numerator sin to the power of 4 space straight x over denominator straight x to the power of 4 end fraction times limit as straight x rightwards arrow 0 of blank fraction numerator straight x to the power of 6 over denominator sin to the power of 6 space straight x end fraction end cell equals 1 row cell limit as straight x rightwards arrow 0 of blank straight x to the power of straight a over straight x squared times stack text lim end text with straight x rightwards arrow 0 below blank fraction numerator text sin end text to the power of 4 text end text straight x over denominator straight x to the power of 4 end fraction times stack text lim end text with straight x rightwards arrow 0 below blank fraction numerator straight x to the power of 6 over denominator text sin end text to the power of 6 text end text straight x end fraction end cell equals 1 row cell stack text lim end text with x rightwards arrow 0 below blank x to the power of a over x squared times 1 times 1 end cell equals cell 1 space end cell row cell stack text lim end text with x rightwards arrow 0 below blank x to the power of a over x squared end cell equals 1 end table

maka diperoleh:

Oleh karena itu, jawaban yang benar adalah B.

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