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Pertanyaan

Jika 4 lo g ( 2 a ) ( 3 + 2 l o g ( 2 a ) ) = 5 , hasil kali akar-akar persamaan tersebut adalah ...

Jika , hasil kali akar-akar persamaan tersebut adalah ...

  1. 1 over 32

  2. 1 over 8

  3. 1 fourth

  4. 1

  5. 8

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S. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Prof. DR. Hamka

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

jawaban yang tepat adalah A.

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Pembahasan

Ingat sifat logaritma bahwa: Diperoleh persamaan logaritma yaitu: Misal: , maka: Sehingga diperoleh: Hasil kali akar-akar, yaitu: Hasil kali akar-akar persamaan tersebut adalah . Jadi, jawaban yang tepat adalah A.

Ingat sifat logaritma bahwa:

table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript a space x to the power of b end cell equals cell b times scriptbase log space x end scriptbase presuperscript a end cell row cell scriptbase log space b to the power of d end scriptbase presuperscript a to the power of c end presuperscript end cell equals cell d over c times scriptbase log space b end scriptbase presuperscript a end cell end table

Diperoleh persamaan logaritma yaitu:

table attributes columnalign left center center end attributes row cell scriptbase log open parentheses 2 a close parentheses to the power of open parentheses 3 plus scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 close parentheses end exponent end scriptbase presuperscript 4 end cell equals 5 row cell open parentheses 3 plus scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 close parentheses times scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 4 end cell equals 5 row cell 3 times scriptbase log open parentheses 2 a close parentheses plus scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 times scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 4 end scriptbase presuperscript 4 end cell equals 5 row cell 3 times scriptbase log open parentheses 2 a close parentheses plus scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 times scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 squared end presuperscript end scriptbase presuperscript 2 squared end presuperscript end cell equals 5 row cell 3 times 1 half scriptbase log open parentheses 2 a close parentheses plus scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 times 1 half times end scriptbase presuperscript 2 scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 end cell equals 5 row cell 3 over 2 times scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 plus fraction numerator scriptbase log open parentheses 2 a close parentheses squared end scriptbase presuperscript 2 over denominator 2 end fraction end cell equals 5 row cell 3 times scriptbase log open parentheses 2 a close parentheses plus scriptbase log open parentheses 2 a close parentheses squared end scriptbase presuperscript 2 end scriptbase presuperscript 2 end cell equals 10 end table

Misal: scriptbase log open parentheses 2 a close parentheses equals x end scriptbase presuperscript 2, maka:

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell table attributes columnalign left center center end attributes row cell 3 times scriptbase log open parentheses 2 a close parentheses plus scriptbase log open parentheses 2 a close parentheses squared end scriptbase presuperscript 2 end scriptbase presuperscript 2 end cell equals 10 row cell 3 x plus x squared end cell equals 10 row cell x squared plus 3 x minus 10 end cell equals 0 row cell x squared plus 5 x minus 2 x minus 10 end cell equals 0 row cell x open parentheses x plus 5 close parentheses minus 2 open parentheses x plus 5 close parentheses end cell equals 0 row cell open parentheses x plus 5 close parentheses open parentheses x minus 2 close parentheses end cell equals 0 end table end cell end table

open parentheses x plus 5 close parentheses open parentheses x minus 2 close parentheses equals 0 x subscript 1 equals negative 5 comma space x subscript 2 equals 2

Sehingga diperoleh:

table attributes columnalign right center left end attributes row cell scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 end cell equals cell negative 5 end cell row cell a subscript 1 end cell equals cell 2 to the power of negative 5 minus 1 end exponent end cell row cell a subscript 1 end cell equals cell 2 to the power of negative 6 end exponent end cell row cell a subscript 1 end cell equals cell 1 over 2 to the power of 6 end cell row cell a subscript 1 end cell equals cell 1 over 64 end cell row space space space row cell scriptbase log open parentheses 2 a close parentheses end scriptbase presuperscript 2 end cell equals 2 row cell a subscript 2 end cell equals cell 2 to the power of 2 minus 1 end exponent end cell row cell a subscript 2 end cell equals 2 end table

Hasil kali akar-akar, yaitu:

table attributes columnalign right center left columnspacing 0px end attributes row cell a subscript 1 times a subscript 2 end cell equals cell 1 over 64 times 2 end cell row blank equals cell 1 over 32 end cell end table

Hasil kali akar-akar persamaan tersebut adalah 1 over 32.

Jadi, jawaban yang tepat adalah A.

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Tentukan nilai-nilai x yang memenuhi persamaanlogaritma berikut! a . 1 0 4 l o g x − 7 ( 1 0 2 l o g x ) + 10 = 0

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