Iklan

Pertanyaan

Jika diketahui koordinat titik A (2, -1, -2) dan B (1, 4, -8), maka nilai sinus sudut antara titik A dan B adalah …

Jika diketahui koordinat titik A (2, -1, -2) dan B (1, 4, -8), maka nilai sinus sudut antara titik A dan B adalah …

  1. begin mathsize 14px style fraction numerator square root of 533 over denominator 27 end fraction end style

  2. begin mathsize 14px style fraction numerator square root of 53 over denominator 27 end fraction end style

  3. begin mathsize 14px style 14 over 27 end style

  4. begin mathsize 14px style 27 over 14 end style

  5. begin mathsize 14px style fraction numerator 14 over denominator square root of 533 end fraction end style

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

02

:

28

:

38

Klaim

Iklan

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style open vertical bar A with rightwards arrow on top close vertical bar equals square root of 2 squared plus left parenthesis negative 1 right parenthesis squared plus left parenthesis negative 2 right parenthesis squared end root equals 3 open vertical bar B with rightwards arrow on top close vertical bar equals square root of 1 squared plus 4 squared plus left parenthesis negative 8 right parenthesis squared end root equals 9 A with rightwards arrow on top space. space space B with rightwards arrow on top equals open parentheses 2 close parentheses open parentheses 1 close parentheses plus open parentheses negative 1 close parentheses open parentheses 4 close parentheses plus open parentheses negative 2 close parentheses open parentheses negative 8 close parentheses equals 14 cos space theta equals fraction numerator A with rightwards arrow on top space. space space B with rightwards arrow on top over denominator open vertical bar A with rightwards arrow on top close vertical bar open vertical bar B with rightwards arrow on top close vertical bar end fraction equals fraction numerator 14 over denominator left parenthesis 3 right parenthesis left parenthesis 9 right parenthesis end fraction equals 14 over 27 Dengan space menggunakan space aturan space trigonometri dalam space segitiga space siku minus siku comma space maka sin space theta equals fraction numerator square root of 533 over denominator 27 end fraction    end style

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

Diketahui vektor-vektor u = i + 2 ​ j ​ + 5 ​ k dan v = i − 2 ​ j ​ + 5 ​ k . Sudut antara vektor u dan v adalah .... ( UN 2010)

2

4.9

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia