RoboguruRoboguru
SD

Jika y=2x+1 digeser sejauh a satuan ke kanan dan sejauh b satuan ke bawah, kemudian dicerminkan terhadap sumbu-y , bayangannya menjadi y=ax+2b. Nilai dari 3ab adalah ....

Pertanyaan

Jika begin mathsize 14px style straight y equals 2 straight x plus 1 space end styledigeser sejauh a satuan ke kanan dan sejauh b satuan ke bawah, kemudian dicerminkan terhadap sumbu-y , bayangannya menjadi begin mathsize 14px style straight y equals ax plus 2 straight b end style. Nilai dari begin mathsize 14px style 3 ab end style adalah .... undefined 

  1. begin mathsize 14px style negative 15 end style undefined 

  2. begin mathsize 14px style negative 12 end style undefined 

  3. begin mathsize 14px style negative 10 end style undefined 

  4. begin mathsize 14px style negative 6 end style undefined 

  5. begin mathsize 14px style 0 end style undefined 

F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Pembahasan

Garis undefineddigeser sejauh a satuan ke kanan dan sejauh b satuan ke bawah, maka

begin mathsize 14px style open parentheses table row cell straight x to the power of straight apostrophe end cell row cell straight y to the power of straight apostrophe end cell end table close parentheses equals open parentheses table row straight x row straight y end table close parentheses plus open parentheses table row straight a row cell negative straight b end cell end table close parentheses open parentheses table row cell straight x to the power of straight apostrophe end cell row cell straight y to the power of straight apostrophe end cell end table close parentheses equals open parentheses table row cell straight x plus straight a end cell row cell straight y minus straight b end cell end table close parentheses end style 

sehingga begin mathsize 14px style straight x equals straight x to the power of apostrophe minus straight a end style dan begin mathsize 14px style straight y equals straight y to the power of straight apostrophe plus straight b end style.

Dengan substitusi begin mathsize 14px style straight x equals straight x to the power of apostrophe minus straight a end style dan begin mathsize 14px style straight y equals straight y to the power of straight apostrophe plus straight b end style ke undefined, maka bayangan garis undefinedhasil pergeseran di atas adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight y to the power of straight apostrophe plus straight b end cell equals cell 2 open parentheses straight x to the power of straight apostrophe minus straight a close parentheses plus 1 end cell row cell straight y to the power of straight apostrophe end cell equals cell 2 straight x plus 1 minus 2 straight a minus straight b end cell row blank rightwards arrow cell straight y equals 2 straight x plus 1 minus 2 straight a minus straight b end cell end table end style 

Kemudian garis tersebut dicerminkan terhadap sumbu-y, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row cell straight x to the power of straight apostrophe end cell row cell straight y to the power of straight apostrophe end cell end table close parentheses end cell equals cell open parentheses table row cell negative 1 end cell 0 row 0 1 end table close parentheses open parentheses table row straight x row straight y end table close parentheses end cell row blank equals cell open parentheses table row cell negative straight x end cell row straight y end table close parentheses end cell end table end style 

sehinggaError converting from MathML to accessible text. dan begin mathsize 14px style straight y equals straight y to the power of straight apostrophe end style.

Dengan substitusi Error converting from MathML to accessible text. dan begin mathsize 14px style straight y equals straight y to the power of straight apostrophe end style ke , maka hasil pencerminan garis begin mathsize 14px style straight y equals 2 straight x plus 1 minus 2 straight a minus straight b space end styleterhadap sumbu-y adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight y straight apostrophe end cell equals cell negative 2 straight x straight apostrophe plus 1 minus 2 straight a minus straight b end cell row blank rightwards arrow cell straight straight y equals negative 2 straight x plus 1 minus 2 straight a minus straight b end cell end table end style 

Karena garis begin mathsize 14px style straight y equals negative 2 straight x plus 1 minus 2 straight a minus straight b end style sama dengan begin mathsize 14px style straight y equals ax plus straight b end style, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell negative 2 straight x end cell equals ax row straight a equals cell negative 2 end cell end table end style

dan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 1 minus 2 straight a minus straight b end cell equals cell 2 straight b end cell row cell 1 minus 2 left parenthesis negative 2 right parenthesis minus straight b end cell equals cell 2 straight b end cell row cell 1 plus 4 end cell equals cell 3 straight b end cell row cell 3 straight b end cell equals 5 row straight b equals cell 5 over 3 end cell end table end style

Dengan demikian, kita peroleh

begin mathsize 14px style 3 ab equals 3 left parenthesis negative 2 right parenthesis open parentheses 5 over 3 close parentheses equals negative 10 end style

Jadi, jawaban yang tepat adalah C. undefined 

Untuk mempelajarinya lebih jelas, tonton video selanjutnya.

93

5.0 (3 rating)

Pertanyaan serupa

Jika  dan , maka nilai dari x→∞lim​det(A)det(B)​ adalah ....

14

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia