Jika f(x)=x1​+1 dan (f∘g)(x)=1+x1​. Nilai g(2)=....

Pertanyaan

Jika  dan . Nilai ....

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F. Ayudhita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Pembahasan

size 14px left parenthesis size 14px f size 14px ring operator size 14px g size 14px right parenthesis size 14px left parenthesis size 14px x size 14px right parenthesis size 14px equals fraction numerator size 14px 1 over denominator size 14px 1 size 14px plus size 14px x end fraction size 14px f begin mathsize 14px style left parenthesis g open parentheses x close parentheses right parenthesis end style size 14px equals fraction numerator size 14px 1 over denominator size 14px 1 size 14px plus size 14px x end fraction fraction numerator size 14px 1 over denominator size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis end fraction size 14px plus size 14px 1 size 14px equals fraction numerator size 14px 1 over denominator size 14px 1 size 14px plus size 14px x end fraction fraction numerator size 14px 1 over denominator size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis end fraction size 14px plus size 14px 1 size 14px minus size 14px 1 size 14px equals fraction numerator size 14px 1 over denominator size 14px 1 size 14px plus size 14px x end fraction size 14px minus size 14px 1 fraction numerator size 14px 1 over denominator size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis end fraction size 14px equals fraction numerator size 14px 1 over denominator size 14px 1 size 14px plus size 14px x end fraction size 14px minus fraction numerator size 14px 1 size 14px plus size 14px x over denominator size 14px 1 size 14px plus size 14px x end fraction fraction numerator size 14px 1 over denominator size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis end fraction size 14px equals fraction numerator size 14px 1 size 14px minus size 14px left parenthesis size 14px 1 size 14px plus size 14px x size 14px right parenthesis over denominator size 14px 1 size 14px plus size 14px x end fraction fraction numerator size 14px 1 over denominator size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis end fraction size 14px equals fraction numerator size 14px 1 size 14px minus size 14px 1 size 14px minus size 14px x over denominator size 14px 1 size 14px plus size 14px x end fraction fraction numerator size 14px 1 over denominator size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis end fraction size 14px equals fraction numerator size 14px minus size 14px x over denominator size 14px 1 size 14px plus size 14px x end fraction size 14px g size 14px left parenthesis size 14px x size 14px right parenthesis size 14px equals fraction numerator size 14px 1 size 14px plus size 14px x over denominator size 14px minus size 14px x end fraction

Karena kita akan mencari begin mathsize 14px style g left parenthesis 2 right parenthesis end style sehingga begin mathsize 14px style x equals 2 end style :

begin mathsize 14px style g left parenthesis 2 right parenthesis equals fraction numerator 1 plus 2 over denominator negative 2 end fraction g left parenthesis 2 right parenthesis equals fraction numerator 3 over denominator negative 2 end fraction equals negative 1 comma 5 end style

 

Jadi, jawaban yang tepat adalah B.

60

5.0 (3 rating)

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