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Jika a , b , c , dan d memenuhi persamaan ( a 2 b ​ c d ​ ) − ( 2 d c ​ b 2 a ​ ) = ( 1 − 1 ​ − 1 1 ​ ) Tentukanlah nilai a + b + c + d = ...

Jika  dan  memenuhi persamaan

 

Tentukanlah nilai  

  1. ...space 

  2. ...space 

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Jawaban terverifikasi

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nilai .

nilai begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank b end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank c end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table equals left parenthesis negative 1 right parenthesis plus left parenthesis negative 2 right parenthesis plus left parenthesis negative 3 right parenthesis plus left parenthesis negative 1 right parenthesis equals negative 7 end style

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Menurut aturan kesamaan dua matriks, diperoleh: 1. 2. 3. 4. Berarti dan Jadi, nilai .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row a c row cell 2 b end cell d end table close parentheses minus open parentheses table row cell 2 d end cell b row c cell 2 a end cell end table close parentheses end cell equals cell open parentheses table row 1 cell negative 1 end cell row cell negative 1 end cell 1 end table close parentheses end cell row cell open parentheses table row cell a minus 2 d end cell cell c minus b end cell row cell 2 b minus c end cell cell d minus 2 a end cell end table close parentheses end cell equals cell open parentheses table row 1 cell negative 1 end cell row cell negative 1 end cell 1 end table close parentheses end cell end table end style  

Menurut aturan kesamaan dua matriks, diperoleh:

1. begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell a minus 2 d end cell equals 1 row blank left right double arrow cell a equals 1 plus 2 d end cell end table end style  

2. begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell c minus b end cell equals cell negative 1 end cell row blank left right double arrow cell c equals negative 1 plus b end cell end table end style  

3. begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 b minus c end cell equals cell negative 1 end cell row cell 2 b minus left parenthesis negative 1 plus b right parenthesis end cell equals cell negative 1 space left parenthesis substitusi space nilai space c space pada space poin space 2 right parenthesis end cell row cell 2 b plus 1 minus b end cell equals cell negative 1 end cell row b equals cell negative 2 end cell end table end style  

4. begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell d minus 2 a end cell equals 1 row cell d minus 2 left parenthesis 1 plus 2 d right parenthesis end cell equals cell 1 space left parenthesis substitusi space nilai space a space pada space poin space 1 right parenthesis end cell row cell d minus 2 minus 4 d end cell equals 1 row cell negative 3 d end cell equals 3 row d equals cell negative 1 end cell end table end style  

Berarti 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row a equals cell 1 plus 2 d end cell row blank equals cell 1 plus 2 left parenthesis negative 1 right parenthesis end cell row blank equals cell 1 minus 2 end cell row blank equals cell negative 1 end cell end table end style   dan begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row c equals cell negative 1 plus b end cell row blank equals cell negative 1 plus left parenthesis negative 2 right parenthesis end cell row blank equals cell negative 3 end cell end table end style   

Jadi, nilai begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank b end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank c end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table equals left parenthesis negative 1 right parenthesis plus left parenthesis negative 2 right parenthesis plus left parenthesis negative 3 right parenthesis plus left parenthesis negative 1 right parenthesis equals negative 7 end style

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Diketahui matriks A = ( − 1 2 ​ − 3 x + 2 ​ ) , B = ( − 6 3 y − 1 ​ 0 − 9 ​ ) , dan C = ( 4 − 6 ​ − 1 3 ​ ) . Jika 2A - B = C T dengan C T adalah transpos dari matriks C, nilai x + y = ....

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