Iklan

Pertanyaan

Jika x 1 ​ dan x 2 ​ memenuhi 2 sin x + sec x - 2 tan x - 1 = 0, maka nilai sin + cos yang mungkin adalah ....

Jika dan memenuhi 2 sin x + sec x - 2 tan x - 1 = 0, maka nilai sin begin mathsize 14px style straight x subscript 1 end style + cos begin mathsize 14px style straight x subscript 2 end style yang mungkin adalah ....

  1. begin mathsize 12px style 4 over 5 end style

  2. begin mathsize 12px style 3 over 4 end style

  3. begin mathsize 12px style 4 over 3 end style

  4. begin mathsize 12px style 3 over 2 end style

  5. 2

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

01

:

01

:

03

:

52

Klaim

Iklan

A. Rizky

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style 2 space sin space invisible function application straight x plus sec invisible function application space straight x minus 2 space tan space invisible function application straight x minus 1 equals 0  2 space sin space invisible function application straight x plus fraction numerator 1 over denominator cos space invisible function application straight x end fraction minus fraction numerator 2 space sin invisible function application space straight x over denominator cos space invisible function application straight x end fraction minus 1 equals 0  2 space sin space invisible function application straight x minus 1 minus open parentheses fraction numerator 2 space sin invisible function application space straight x minus 1 over denominator cos space invisible function application straight x end fraction close parentheses equals 0  open parentheses 2 space sin invisible function application space straight x minus 1 close parentheses open parentheses 1 minus fraction numerator 1 over denominator cos space invisible function application straight x end fraction close parentheses equals 0    Maka colon  2 space sin space invisible function application straight x equals 1 rightwards double arrow sin invisible function application space straight x equals 1 half  1 minus fraction numerator 1 over denominator cos space invisible function application straight x end fraction equals 0 rightwards double arrow fraction numerator 1 over denominator cos space invisible function application straight x end fraction equals 1 rightwards double arrow cos invisible function application space straight x equals 1  Sehingga  sin invisible function application space straight x subscript 1 plus cos space invisible function application straight x subscript 2 equals 1 half plus 1 equals 3 over 2 end style

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

5

Iklan

Pertanyaan serupa

Himpunan penyelesaian dari sin 2 x + 3 sin x + 2 = 0 adalah ...

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia