Roboguru

Jika  dan , maka  sama dengan ...

Pertanyaan

Jika f left parenthesis x right parenthesis equals fraction numerator 1 over denominator 2 x minus 1 end fraction comma space x not equal to 1 half dan open parentheses f ring operator g close parentheses open parentheses x close parentheses equals fraction numerator x over denominator 3 x minus 2 end fraction comma space x not equal to 2 over 3, maka g left parenthesis x right parenthesis sama dengan ...

  1. 2 plus 1 over x 

  2. 1 plus 2 over x 

  3. 2 minus 1 over x 

  4. 1 minus 2 over x 

  5. 2 minus fraction numerator 1 over denominator 2 x end fraction 

Pembahasan Soal:

Diketahui f left parenthesis x right parenthesis equals fraction numerator 1 over denominator 2 x minus 1 end fraction comma space x not equal to 1 half dan open parentheses f ring operator g close parentheses open parentheses x close parentheses equals fraction numerator x over denominator 3 x minus 2 end fraction comma space x not equal to 2 over 3. Maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses f ring operator g close parentheses open parentheses x close parentheses end cell equals cell fraction numerator x over denominator 3 x minus 2 end fraction end cell row cell f open parentheses g left parenthesis x right parenthesis close parentheses end cell equals cell fraction numerator x over denominator 3 x minus 2 end fraction end cell row cell fraction numerator 1 over denominator 2 g left parenthesis x right parenthesis minus 1 end fraction end cell equals cell fraction numerator x over denominator 3 x minus 2 end fraction end cell row cell x open parentheses 2 g left parenthesis x right parenthesis minus 1 close parentheses end cell equals cell 3 x minus 2 end cell row cell 2 x open parentheses g left parenthesis x right parenthesis close parentheses minus x end cell equals cell 3 x minus 2 end cell row cell 2 x open parentheses g left parenthesis x right parenthesis close parentheses end cell equals cell 3 x plus x minus 2 end cell row cell 2 x open parentheses g left parenthesis x right parenthesis close parentheses end cell equals cell 4 x minus 2 end cell row cell g left parenthesis x right parenthesis end cell equals cell fraction numerator 4 x minus 2 over denominator 2 x end fraction end cell row cell g left parenthesis x right parenthesis end cell equals cell 2 minus 1 over x. end cell end table 

Dengan demikian, fungsi g left parenthesis x right parenthesis yang sesuai adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell g left parenthesis x right parenthesis end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 1 over x end cell end table.

Oleh karena itu, jawaban yang benar adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 19 Mei 2021

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved