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Jika dan maka f(x)=...

Jika f to the power of apostrophe apostrophe apostrophe end exponent open parentheses x close parentheses equals 2 x comma space f to the power of apostrophe apostrophe end exponent open parentheses 0 close parentheses equals 2 comma space f to the power of apostrophe open parentheses 1 close parentheses equals 2 dan f open parentheses 2 close parentheses equals 4 maka f(x)=...

  1. 12 x to the power of 4 minus x squared plus 3 x minus 2

  2. 1 over 12 x to the power of 4 minus x squared plus 1 third x minus 2 over 3

  3. x to the power of 4 plus 12 x squared minus 4 x plus 8

  4. 1 over 12 x to the power of 4 plus x squared minus 1 third x minus 2 over 3

  5. x squared 12 x squared plus 4 x minus 8

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N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

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Pembahasan

f to the power of apostrophe apostrophe apostrophe end exponent open parentheses x close parentheses equals 2 x f to the power of apostrophe apostrophe end exponent open parentheses x close parentheses equals integral 2 x d x equals x squared plus C f to the power of apostrophe apostrophe end exponent open parentheses 0 close parentheses equals 2 0 squared plus C equals 2 C equals 2 therefore f to the power of apostrophe apostrophe end exponent open parentheses x close parentheses equals x squared plus 2

f to the power of apostrophe open parentheses x close parentheses equals integral open parentheses x squared plus 2 close parentheses d x f to the power of apostrophe open parentheses x close parentheses equals 1 third x cubed plus 2 x plus C f to the power of apostrophe open parentheses 1 close parentheses equals 2 1 third open parentheses 1 close parentheses cubed plus 2 open parentheses 1 close parentheses plus C equals 2 C equals negative 1 third f to the power of apostrophe open parentheses x close parentheses equals 1 third x cubed plus 2 x minus 1 third

f open parentheses x close parentheses equals integral open parentheses 1 third x cubed plus 2 x minus 1 third close parentheses d x f open parentheses x close parentheses equals 1 over 12 x to the power of 4 plus x squared minus 1 third x plus C f open parentheses 2 close parentheses equals 4 1 over 12 open parentheses 2 close parentheses to the power of 4 plus 2 squared minus 1 third open parentheses 2 close parentheses plus C equals 4 C equals negative 2 over 3 therefore f open parentheses x close parentheses equals 1 over 12 x to the power of 4 plus x squared minus 1 third x minus 2 over 3

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