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Hasil ∫ ​ x 2 − 4 x + 5 ​ 4 x − 8 ​ d x = ....

Hasil

  1. 4 square root of x squared minus 4 x plus 5 end root plus C

  2. 2 square root of x squared minus 4 x plus 5 end root plus C

  3. 3 over 2 square root of x squared minus 4 x plus 5 end root plus C

  4. negative 3 over 2 square root of x squared minus 4 x plus 5 end root plus C

  5. negative 4 square root of x squared minus 4 x plus 5 end root plus C

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A. Acfreelance

Master Teacher

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Pembahasan

M i s a l space u equals square root of x squared minus 4 x plus 5 end root comma space m a k a space d u equals fraction numerator x minus 2 over denominator square root of x squared minus 4 x plus 5 end root end fraction d x comma space S e h i n g g a comma  integral subscript space superscript space fraction numerator 4 x minus 8 over denominator square root of x squared minus 4 x plus 5 end root end fraction space d x equals space integral subscript space superscript space fraction numerator 4 open parentheses x minus 2 close parentheses over denominator square root of x squared minus 4 x plus 5 end root end fraction space d x space  equals 4 integral subscript space superscript space fraction numerator open parentheses x minus 2 close parentheses over denominator square root of x squared minus 4 x plus 5 end root end fraction space d x space  equals 4 integral subscript space superscript space d u space  equals 4 u plus C  equals 4 square root of x squared minus 4 x plus 5 end root plus C

Latihan Bab

Pengenalan Integral

Integral Tak Tentu

Integral Substitusi

Aplikasi Integral Tak Tentu

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