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Hasil dari ∫ 3 ( 2 x − 1 ) 2 ​ d x = ...

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  1. 3 over 5 left parenthesis 2 x minus 1 right parenthesis cube root of left parenthesis x minus 1 right parenthesis squared end root plus c

  2. 6 over 5 left parenthesis 2 x minus 1 right parenthesis cube root of left parenthesis x minus 1 right parenthesis squared end root plus c

  3. 6 over 5 left parenthesis 2 x minus 1 right parenthesis square root of left parenthesis x minus 1 right parenthesis squared end root plus c

  4. 3 over 10 left parenthesis x minus 1 right parenthesis cube root of left parenthesis 2 x minus 1 right parenthesis squared end root plus c

  5. 3 over 5 left parenthesis 2 x minus 1 right parenthesis square root of left parenthesis x minus 1 right parenthesis squared end root plus c

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

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Pembahasan

integral cube root of open parentheses 2 x minus 1 close parentheses squared end root d x equals integral left parenthesis 2 x minus 1 right parenthesis to the power of 2 over 3 end exponent d x  equals 3 over 5 open parentheses 2 x minus 1 close parentheses to the power of 5 over 3 end exponent 1 half plus c  equals 3 over 10 left parenthesis 2 x minus 1 right parenthesis to the power of 5 over 3 end exponent plus c

equals 3 over 10 left parenthesis x minus 1 right parenthesis cube root of left parenthesis 2 x minus 1 right parenthesis squared end root plus c

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