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Hasil dari ∫ ( 2 x 3 − 1 ) + c ​ 18 x 2 ​ d x = ...

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  1. 9 over 2 cube root of open parentheses 2 x cubed minus 1 close parentheses squared end root plus c

  2. 9 over 2 left parenthesis 2 x cubed minus 1 right parenthesis root index blank of open parentheses 2 x cubed minus 1 close parentheses end root plus c

  3. 2 cube root of open parentheses 2 x cubed minus 1 close parentheses squared end root plus c

  4. 2 left parenthesis 2 x cubed minus 1 right parenthesis squared. square root of 2 x cubed minus 1 end root plus c

  5. 2 left parenthesis 2 x cubed minus 1 right parenthesis. square root of 2 x cubed minus 1 end root plus c

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N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

U equals space 2 x space cubed space minus space 1  d u space equals space 6 x squared d x  d x equals fraction numerator 1 over denominator 6 x squared end fraction d u  integral 18 x squared space left parenthesis 2 x cubed minus space 1 right parenthesis to the power of 1 half end exponent d x equals integral 18 x squared. u to the power of 1 half end exponent. fraction numerator 1 over denominator 6 x squared end fraction d u  equals integral 3 U to the power of 1 half end exponent d u  equals 3.2 over 3 U to the power of 3 over 2 end exponent plus c  equals 2 left parenthesis 2 x cubed minus 1 right parenthesis to the power of 3 over 2 end exponent plus c  equals 2 left parenthesis 2 x cubed minus 1 right parenthesis square root of 2 x cubed minus 1 end root plus c

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