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Nilai dari

Pertanyaan

Nilai dari integral open parentheses 3 x minus 1 close parentheses to the power of 7 space d x equals.... 

Pembahasan Soal:

Misalkan u equals 3 x minus 1, sehingga d u equals 3 space d x left right arrow fraction numerator d u over denominator 3 end fraction equals d x 

table attributes columnalign right center left columnspacing 0px end attributes row cell integral open parentheses 3 x minus 1 close parentheses to the power of 7 space d x end cell equals cell integral u to the power of 7 space fraction numerator d u over denominator 3 end fraction end cell row blank equals cell 1 third integral u to the power of 7 space d u end cell row blank equals cell 1 third open square brackets fraction numerator 1 over denominator 7 plus 1 end fraction u to the power of 7 plus 1 end exponent plus C close square brackets end cell row blank equals cell 1 third open square brackets 1 over 8 u to the power of 8 plus C close square brackets end cell row blank equals cell 1 third open square brackets 1 over 8 open parentheses 3 x minus 1 close parentheses to the power of 8 plus C close square brackets end cell row blank equals cell 1 over 24 open parentheses 3 x minus 1 close parentheses to the power of 8 plus C end cell end table 

Jadi, nilai dari Error converting from MathML to accessible text.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

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