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Hasil dari begin mathsize 12px style integral open parentheses cos cubed 2 x sin 2 x close parentheses d x end style = ...

  1. begin mathsize 12px style 1 fourth cos to the power of 4 2 x plus C end style

  2. begin mathsize 12px style 1 fourth sin to the power of 4 2 x plus C end style

  3. begin mathsize 12px style 1 over 6 cos to the power of 4 2 x plus C end style

  4. begin mathsize 12px style negative 1 over 8 cos to the power of 4 2 x plus C end style

  5. begin mathsize 12px style negative 1 over 8 sin to the power of 4 2 x plus C end style

Y. Laksmi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

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Pembahasan

Misalkan u = cos 2x

du = - 2sin2xdx

begin mathsize 12px style negative 1 half d u equals sin 2 x d x  integral open parentheses cos cubed 2 x sin 2 x close parentheses d x equals integral negative 1 half u cubed d u  equals negative 1 half open square brackets fraction numerator 1 over denominator 3 plus 1 end fraction u to the power of 3 plus 1 end exponent close square brackets plus C  equals negative 1 half open square brackets 1 fourth u to the power of 4 close square brackets plus C  equals negative 1 over 8 u to the power of 4 plus C  equals negative 1 over 8 cos to the power of 4 2 x plus C end style

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