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Hasil dari begin mathsize 14px style integral sin to the power of 5 invisible function application space 2 x space cos space invisible function application 2 x space d x end style = ....

  1. begin mathsize 14px style negative 1 fifth sin to the power of 6 space 2 x plus C end style

  2. begin mathsize 14px style negative 1 over 10 sin to the power of 6 space 2 x plus C end style

  3. begin mathsize 14px style negative 1 over 12 sin to the power of 6 space 2 x plus C end style

  4. begin mathsize 14px style 1 over 12 sin to the power of 6 space 2 x plus C end style

  5. begin mathsize 14px style 1 over 10 sin to the power of 6 space 2 x plus C end style

S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style misal colon space straight u equals sin space invisible function application 2 straight x  du equals 2 space cos invisible function application space 2 straight x space dx  1 half du equals cos invisible function application space 2 straight x space dx    integral sin to the power of 5 invisible function application space 2 straight x space cos space invisible function application 2 straight x space dx  equals integral straight u to the power of 5.1 half du  equals 1 half straight space.1 over 6 straight u to the power of 6 plus straight C  equals 1 over 12 straight u to the power of 6 plus straight C  equals 1 over 12 sin to the power of 6 invisible function application space 2 straight x plus straight C end style

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