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Hasil ∫ 4 x ( 4 x 2 − 3 ) 4 d x adalah ....

Hasil  adalah ....

  1. begin mathsize 14px style 1 over 10 open parentheses 4 x squared minus 3 close parentheses to the power of 5 space plus C end style

  2. begin mathsize 14px style 1 fifth open parentheses 4 x squared minus 3 close parentheses to the power of 5 space plus C end style

  3. begin mathsize 14px style 2 over 5 open parentheses 4 x squared minus 3 close parentheses to the power of 5 space plus C end style

  4. begin mathsize 14px style open parentheses 4 x squared minus 3 close parentheses to the power of 5 space plus C end style

  5. begin mathsize 14px style 2 open parentheses 4 x squared minus 3 close parentheses to the power of 5 space plus C end style

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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begin mathsize 14px style integral 4 straight x open parentheses 4 straight x squared minus 3 close parentheses to the power of 4 dx  Misalkan space straight u equals 4 straight x squared minus 3 rightwards double arrow du equals 8 straight x space dx rightwards double arrow 1 half du equals 4 straight x space dx  integral 4 straight x open parentheses 4 straight x squared minus 3 close parentheses to the power of 4 dx  equals integral open parentheses 4 straight x squared minus 3 close parentheses to the power of 4.4 straight x space dx  equals integral straight u to the power of 4 open parentheses 1 half du close parentheses  equals integral 1 half straight u to the power of 4 du  equals 1 over 10 straight u to the power of 5 plus straight C  equals 1 over 10 open parentheses 4 straight x squared minus 3 close parentheses to the power of 5 plus straight C end style

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