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Hasil ∫ ( 4 x 3 − 6 x 2 + 2 x + 3 ) d x adalah ....

Hasil  adalah ....

  1. x to the power of 4 minus 3 x cubed plus x squared plus 3 x plus C  

  2. x to the power of 4 minus 2 x cubed plus x squared plus 3 x plus C  

  3. 2 x to the power of 4 minus 3 x cubed plus x squared plus 3 x plus C 

  4. 2 x to the power of 4 minus 2 x cubed plus x squared plus 3 x plus C 

  5.  4 x to the power of 4 minus 2 x cubed plus x squared plus 3 x plus C 

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N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

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Pembahasan

Rumus Integral Aljabar. Jadi, hasil adalah . Jadi, jawaban yang tepat adalah B.

Rumus Integral Aljabar.

integral space a x to the power of n d x equals fraction numerator a over denominator n plus 1 end fraction x to the power of n plus 1 end exponent plus C 

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell integral space open parentheses 4 x cubed minus 6 x squared plus 2 x plus 3 close parentheses space d x end cell row blank equals cell fraction numerator 4 over denominator 3 plus 1 end fraction x to the power of 3 plus 1 end exponent minus fraction numerator 6 over denominator 2 plus 1 end fraction x to the power of 2 plus 1 end exponent plus fraction numerator 2 over denominator 1 plus 1 end fraction x to the power of 1 plus 1 end exponent plus 3 x plus C end cell row blank equals cell 4 over 4 x to the power of 4 minus 6 over 3 x cubed plus 2 over 2 x squared plus 3 x plus C end cell row blank equals cell x to the power of 4 minus 2 x cubed plus x squared plus 3 x plus C end cell end table  

Jadi, hasil integral space open parentheses 4 x cubed minus 6 x squared plus 2 x plus 3 close parentheses space d x adalah x to the power of 4 minus 2 x cubed plus x squared plus 3 x plus C.

Jadi, jawaban yang tepat adalah B.

 

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