Iklan

Pertanyaan

Diketahui vektor p ​ = ⎝ ⎛ ​ 3 − 2 − 1 ​ ⎠ ⎞ ​ dan q ​ = ⎝ ⎛ ​ 2 5 − 3 ​ ⎠ ⎞ ​ . Jika vektor r memenuhi persamaan 2 r + 5 p ​ = 3 q ​ + 4 r , hasil operasi p ​ + q ​ + 2 r adalah ....

Diketahui vektor  . Jika vektor  memenuhi persamaan , hasil operasi  adalah ....

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

07

:

40

:

51

Klaim

Iklan

S. Dwi

Master Teacher

Jawaban terverifikasi

Jawaban

hasil operasi .

hasil operasi table attributes columnalign right center left columnspacing 0px end attributes row cell p with rightwards arrow on top plus q with rightwards arrow on top plus 2 r with rightwards arrow on top end cell equals cell open parentheses table row 14 row cell negative 22 end cell row 0 end table close parentheses end cell end table.

Pembahasan

Diketahui , serta , maka Jadi, hasil operasi .

Diketahui p with rightwards arrow on top equals open parentheses table row 3 row cell negative 2 end cell row cell negative 1 end cell end table close parentheses space dan space straight q with rightwards arrow on top equals open parentheses table row 2 row 5 row cell negative 3 end cell end table close parentheses, serta 2 r with rightwards arrow on top plus 5 p with rightwards arrow on top equals 3 q with rightwards arrow on top plus 4 r with rightwards arrow on top, maka

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 r with rightwards arrow on top plus 5 p with rightwards arrow on top end cell equals cell 3 q with rightwards arrow on top plus 4 r with rightwards arrow on top end cell row cell 5 open parentheses table row 3 row cell negative 2 end cell row cell negative 1 end cell end table close parentheses end cell equals cell 3 open parentheses table row 2 row 5 row cell negative 3 end cell end table close parentheses plus 2 r with rightwards arrow on top end cell row cell 2 r with rightwards arrow on top end cell equals cell open parentheses table row 15 row cell negative 10 end cell row cell negative 5 end cell end table close parentheses minus open parentheses table row 6 row 15 row cell negative 9 end cell end table close parentheses end cell row blank equals cell open parentheses table row 9 row cell negative 25 end cell row 4 end table close parentheses end cell row blank rightwards arrow cell p with rightwards arrow on top plus q with rightwards arrow on top plus 2 r with rightwards arrow on top equals open parentheses table row 3 row cell negative 2 end cell row cell negative 1 end cell end table close parentheses plus open parentheses table row 2 row 5 row cell negative 3 end cell end table close parentheses plus open parentheses table row 9 row cell negative 25 end cell row 4 end table close parentheses end cell row blank equals cell open parentheses table row 14 row cell negative 22 end cell row 0 end table close parentheses end cell end table

Jadi, hasil operasi table attributes columnalign right center left columnspacing 0px end attributes row cell p with rightwards arrow on top plus q with rightwards arrow on top plus 2 r with rightwards arrow on top end cell equals cell open parentheses table row 14 row cell negative 22 end cell row 0 end table close parentheses end cell end table.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

anaa

Pembahasan lengkap banget Ini yang aku cari! Mudah dimengerti Bantu banget Makasih ❤️

Shafa Unnida

Pembahasan lengkap banget Makasih ❤️

Ribby Abriellia

Pembahasan lengkap banget Ini yang aku cari! Makasih ❤️

RistaSn Rista

Pembahasan tidak menjawab soal

Iklan

Pertanyaan serupa

Jika a = ( 1 3 ​ ) , b = ( 0 1 ​ ) dan c = ( 2 5 ​ ) , maka panjang vektor d = 3 a − 2 b + c adalah ...

1

4.5

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02130930000

02130930000

Ikuti Kami

©2026 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia