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Pertanyaan

Diketahui vektor a = ⎣ ⎡ ​ − 3 2 1 ​ ⎦ ⎤ ​ dan b = ⎣ ⎡ ​ 2 0 m ​ ⎦ ⎤ ​ . Jika panjang proyeksi skalar a terhadap b sama dengan 5 ​ , tentukanlah nilai m yang memenuhi! !

Diketahui vektor.  Jika panjang proyeksi skalar  terhadap sama dengan , tentukanlah nilai yang memenuhi! !

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N. Indah

Master Teacher

Mahasiswa/Alumni Universitas Diponegoro

Jawaban terverifikasi

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Pembahasan

Diketahui: skalar terhadap sama dengan Ditanyakan: Penyelesaian: Jadi nilai m adalah

Diketahui:

a with rightwards arrow on top equals open square brackets table row cell negative 3 end cell row 2 row 1 end table close square brackets

space b with rightwards arrow on top equals open square brackets table row 2 row 0 row m end table close square brackets

skalar begin mathsize 14px style a with rightwards arrow on top end style terhadap b with rightwards arrow on top sama dengan begin mathsize 14px style square root of 5 end style

Ditanyakan:

m equals...

Penyelesaian:

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar P close vertical bar end cell equals cell fraction numerator open vertical bar a. b close vertical bar over denominator open vertical bar b close vertical bar end fraction end cell row cell square root of 5 end cell equals cell fraction numerator open vertical bar negative 3 open parentheses 2 close parentheses plus 2 open parentheses 0 close parentheses plus 1 open parentheses m close parentheses close vertical bar over denominator square root of 2 squared plus open parentheses m squared close parentheses end root end fraction end cell row cell square root of 5 end cell equals cell fraction numerator open vertical bar negative 6 plus m close vertical bar over denominator square root of 4 plus m squared end root end fraction end cell row cell square root of 5 open parentheses square root of 4 plus m squared end root close parentheses end cell equals cell open vertical bar negative 6 plus m close vertical bar end cell row cell open parentheses square root of 5 close parentheses squared open parentheses open parentheses square root of 4 plus m squared end root close parentheses squared close parentheses end cell equals cell open parentheses negative 6 plus m close parentheses squared end cell row cell 5 open parentheses 4 plus m squared close parentheses end cell equals cell 36 minus 12 m plus m squared end cell row cell 20 plus 5 m squared end cell equals cell 36 minus 12 m plus m squared end cell row cell 5 m squared plus 12 m minus m squared plus 20 minus 36 end cell equals 0 row cell 4 m squared plus 12 m minus 16 end cell equals 0 row cell m squared plus 3 m minus 4 end cell equals 0 row blank blank cell open parentheses m plus 4 close parentheses open parentheses m minus 1 close parentheses m equals negative 4 space atau space m equals 1 end cell end table

Jadi nilai m adalah m equals negative 4 space atau space m equals 1

 

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