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Pertanyaan

Diketahui vektor a with rightwards arrow on top equals open parentheses table row 3 row cell negative 2 end cell end table close parentheses comma space b with rightwards arrow on top equals open parentheses table row 4 row 1 end table close parentheses comma space dan space c with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row cell negative 1 end cell end table close parentheses. Jika 2 a with rightwards arrow on top minus 3 b with rightwards arrow on top plus k c with rightwards arrow on top equals open parentheses table row 0 row cell negative 4 end cell end table close parentheses, dengan k bilangan real, maka nilai k adalah ..

  1. 5 

  2. negative 3 

  3. negative 1 

  4. 1 

  5. 3

S. Nur

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Diketahui vektor a with rightwards arrow on top equals open parentheses table row 3 row cell negative 2 end cell end table close parentheses comma space b with rightwards arrow on top equals open parentheses table row 4 row 1 end table close parentheses comma space c with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row cell negative 1 end cell end table close parentheses dan 2 a with rightwards arrow on top minus 3 b with rightwards arrow on top plus k c with rightwards arrow on top equals open parentheses table row 0 row cell negative 4 end cell end table close parentheses. Maka:

begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell space space space space space space space space space space space space space space space space space space space 2 a with rightwards arrow on top minus 3 b with rightwards arrow on top plus k c with rightwards arrow on top end cell equals cell open parentheses table row 0 row cell negative 4 end cell end table close parentheses end cell row cell 2 open parentheses table row 3 row cell negative 2 end cell end table close parentheses minus 3 open parentheses table row 4 row 1 end table close parentheses plus k open parentheses table row cell negative 2 end cell row cell negative 1 end cell end table close parentheses end cell equals cell open parentheses table row 0 row cell negative 4 end cell end table close parentheses end cell row cell open parentheses table row cell 2 cross times 3 end cell row cell 2 cross times open parentheses negative 2 close parentheses end cell end table close parentheses minus open parentheses table row cell 3 cross times 4 end cell row cell 3 cross times 1 end cell end table close parentheses plus open parentheses table row cell k cross times open parentheses negative 2 close parentheses end cell row cell k cross times open parentheses negative 1 close parentheses end cell end table close parentheses end cell equals cell open parentheses table row 0 row cell negative 4 end cell end table close parentheses end cell row cell space space open parentheses table row 6 row cell negative 4 end cell end table close parentheses minus open parentheses table row 12 row 3 end table close parentheses plus open parentheses table row cell negative 2 k end cell row cell negative k end cell end table close parentheses end cell equals cell open parentheses table row 0 row cell negative 4 end cell end table close parentheses end cell row cell open parentheses table row cell 6 minus 12 plus left parenthesis negative 2 k right parenthesis end cell row cell negative 4 minus 3 plus left parenthesis negative k right parenthesis end cell end table close parentheses end cell equals cell open parentheses table row 0 row cell negative 4 end cell end table close parentheses end cell row cell space space space space space space space space space space space space space space space space space space space space space space open parentheses table row cell negative 6 minus 2 k end cell row cell negative 7 minus k end cell end table close parentheses end cell equals cell open parentheses table row 0 row cell negative 4 end cell end table close parentheses end cell end table end style  

Dari kesamaan vektor di atas, didapat:

table attributes columnalign right center left columnspacing 0px end attributes row cell negative 6 minus 2 k end cell equals 0 row cell space space space space space minus 2 k end cell equals 6 row k equals cell fraction numerator 6 over denominator negative 2 end fraction end cell row cell space space space space space space space space space space space k end cell equals cell negative 3 end cell end table  

Oleh karena itu, jawaban yang tepat adalah B.

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