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Diketahui vektor a = 2 i − 4 j ​ − 6 k dan vektor b = 2 i − 2 j ​ + 4 k .Proyeksi vektorortogonal vektor a pada b adalah ....

Diketahui vektor  dan vektor . Proyeksi vektor ortogonal vektor  pada  adalah ....

  1. begin mathsize 12px style negative 4 i with rightwards arrow on top plus 8 j with rightwards arrow on top plus 12 k with rightwards arrow on top end style

  2. begin mathsize 12px style negative 4 i with rightwards arrow on top plus 4 j with rightwards arrow on top minus 8 k with rightwards arrow on top end style

  3. begin mathsize 12px style negative 2 i with rightwards arrow on top plus 2 j with rightwards arrow on top minus 4 k with rightwards arrow on top end style

  4. begin mathsize 12px style i with rightwards arrow on top plus j with rightwards arrow on top minus 2 k with rightwards arrow on top end style

  5. begin mathsize 12px style negative i with rightwards arrow on top plus j with rightwards arrow on top minus 2 k with rightwards arrow on top end style

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Y. Laksmi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

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Pembahasan

Diketahui: Proyeksi vektorortogonal vektor pada :

Diketahui:

begin mathsize 12px style a with rightwards arrow on top equals 2 i with rightwards arrow on top minus 4 j with rightwards arrow on top minus 6 k with rightwards arrow on top end style 

begin mathsize 12px style b with rightwards arrow on top equals 2 i with rightwards arrow on top minus 2 j with rightwards arrow on top plus 4 k with rightwards arrow on top end style

Proyeksi vektor ortogonal vektor begin mathsize 12px style a with rightwards arrow on top end style pada begin mathsize 12px style b with rightwards arrow on top end style:

begin mathsize 12px style c with rightwards arrow on top equals fraction numerator a with rightwards arrow on top times b with rightwards arrow on top over denominator open vertical bar b with rightwards arrow on top close vertical bar squared end fraction  c with rightwards arrow on top equals fraction numerator open parentheses a subscript x space b subscript x plus a subscript y space b subscript y plus a subscript z space b subscript z close parentheses over denominator open parentheses square root of b subscript x squared plus b subscript y squared plus b subscript z squared end root close parentheses squared end fraction open parentheses 2 i with rightwards arrow on top minus 2 j with rightwards arrow on top plus 4 k with rightwards arrow on top close parentheses  c with rightwards arrow on top equals fraction numerator open parentheses 2 cross times 2 plus open curly brackets negative 4 close curly brackets cross times open curly brackets negative 2 close curly brackets plus open curly brackets negative 6 close curly brackets cross times open curly brackets 4 close curly brackets close parentheses over denominator open parentheses square root of 2 squared plus open parentheses negative 2 close parentheses squared plus 4 squared end root close parentheses squared end fraction open parentheses 2 i with rightwards arrow on top minus 2 j with rightwards arrow on top plus 4 k with rightwards arrow on top close parentheses  c with rightwards arrow on top equals fraction numerator 4 plus 8 minus 24 over denominator 24 end fraction open parentheses 2 i with rightwards arrow on top minus 2 j with rightwards arrow on top plus 4 k with rightwards arrow on top close parentheses  c with rightwards arrow on top equals fraction numerator negative 12 over denominator 24 end fraction open parentheses 2 i with rightwards arrow on top minus 2 j with rightwards arrow on top plus 4 k with rightwards arrow on top close parentheses  c with rightwards arrow on top equals negative i with rightwards arrow on top plus j with rightwards arrow on top minus 2 k with rightwards arrow on top end style

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Diketahui vektor a = ⎝ ⎛ ​ − 1 − 3 2 ​ ⎠ ⎞ ​ dan b = ⎝ ⎛ ​ − 2 6 1 ​ ⎠ ⎞ ​ . Vektor proyeksi ortogonal dari vektor b pada vektor a adalah ....

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