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Diketahui: f ( x ) g ( x ) ​ = = ​ 5 x − 1 x 2 + 3 ​ Tentukanlah ​ ​ ( g ∘ f ) ​ ​ ​ − 1 ​ ​ ​ ( x ) ​ .

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Tentukan terlebih dahulu fungsi komposisi . Misal , maka, : Jadi, .

Tentukan terlebih dahulu fungsi komposisi begin mathsize 14px style open parentheses g ring operator f close parentheses open parentheses x close parentheses end style.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis g ring operator f right parenthesis left parenthesis x right parenthesis end cell equals cell g left parenthesis f open parentheses x close parentheses right parenthesis end cell row cell left parenthesis g ring operator f right parenthesis left parenthesis x right parenthesis end cell equals cell g left parenthesis 5 x minus 1 right parenthesis end cell row cell left parenthesis g ring operator f right parenthesis left parenthesis x right parenthesis end cell equals cell open parentheses 5 x minus 1 close parentheses squared plus 3 end cell row blank blank blank end table end style  

Misal begin mathsize 14px style open parentheses g ring operator f close parentheses to the power of negative 1 end exponent open parentheses x close parentheses equals y end style, maka, begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses g ring operator f close parentheses end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank to the power of negative 1 end exponent end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open parentheses x close parentheses end cell end table end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g ring operator f close parentheses open parentheses x close parentheses end cell equals cell open parentheses 5 x minus 1 close parentheses squared plus 3 end cell row y equals cell open parentheses 5 x minus 1 close parentheses squared plus 3 end cell row cell y minus 3 end cell equals cell open parentheses 5 x minus 1 close parentheses squared end cell row cell open parentheses 5 x minus 1 close parentheses squared end cell equals cell y minus 3 end cell row cell 5 x minus 1 end cell equals cell plus-or-minus square root of y minus 3 end root end cell row cell 5 x end cell equals cell 1 plus-or-minus square root of y minus 3 end root end cell row x equals cell fraction numerator 1 plus-or-minus square root of y minus 3 end root over denominator 5 end fraction end cell row cell open parentheses g ring operator f close parentheses to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator 1 plus-or-minus square root of x minus 3 end root over denominator 5 end fraction end cell end table end style  

Jadi, Error converting from MathML to accessible text..

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