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Diketahui f ( x ) = 4 x + 1 2 − 3 x ​ , x  = − 4 1 ​ Tentukan: b. f − 1 ( x + 1 )

Diketahui  Tentukan:

b.   

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E. Dwi

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

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begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f left parenthesis x right parenthesis end cell equals cell fraction numerator 2 minus 3 x over denominator 4 x plus 1 end fraction end cell row y equals cell fraction numerator 2 minus 3 x over denominator 4 x plus 1 end fraction end cell row cell 4 x y plus y end cell equals cell 2 minus 3 x end cell row cell 4 x y plus 3 x end cell equals cell 2 minus y end cell row cell left parenthesis 4 y plus 3 right parenthesis x end cell equals cell 2 minus y end cell row x equals cell fraction numerator 2 minus y over denominator 4 y plus 3 end fraction end cell row cell f to the power of negative 1 end exponent left parenthesis y right parenthesis end cell equals cell fraction numerator 2 minus y over denominator 4 y plus 3 end fraction end cell row cell f to the power of negative 1 end exponent left parenthesis x right parenthesis end cell equals cell fraction numerator 2 minus x over denominator 4 x plus 3 end fraction end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent left parenthesis x plus 1 right parenthesis end cell equals cell fraction numerator 2 minus open parentheses x plus 1 close parentheses over denominator 4 open parentheses x plus 1 close parentheses plus 3 end fraction end cell row blank blank blank row blank equals cell fraction numerator 2 minus x minus 1 over denominator 4 x plus 4 plus 3 end fraction end cell row blank equals cell fraction numerator 1 minus x over denominator 4 x plus 7 end fraction end cell end table end style 

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