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Pertanyaan

Diketahui segitiga ABC dengan koordinat A ( 2 , –1 , –1 ) , B ( –1 , 4 , –2 ) , dan C ( 5 , 0 , –3 ) . Proyeksi vektor AB pada AC adalah ....

Diketahui segitiga ABC dengan koordinat  dan  Proyeksi vektor  pada  adalah ....

  1. begin mathsize 14px style 1 fourth open parentheses 3 straight i with hat on top plus straight j with hat on top minus 2 straight k with hat on top close parentheses end style 

  2. begin mathsize 14px style 3 over 14 open parentheses 3 straight i with hat on top plus straight j with hat on top minus 2 straight k with hat on top close parentheses end style 

  3. begin mathsize 14px style negative 1 over 7 open parentheses 3 straight i with hat on top plus straight j with hat on top minus 2 straight k with hat on top close parentheses end style 

  4. begin mathsize 14px style negative 3 over 14 open parentheses 3 straight i with hat on top plus straight j with hat on top minus 2 straight k with hat on top close parentheses end style 

  5. begin mathsize 14px style negative 3 over 7 open parentheses 3 straight i with hat on top plus straight j with hat on top minus 2 straight k with hat on top close parentheses end style 

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S. Nur

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

jawaban yang tepat adalah C.space space  

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Pembahasan

Perhatikan bahwa Kemudian, Maka proyeksi vektor pada adalah Jadi, jawaban yang tepat adalah C.

Perhatikan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell AB with rightwards arrow on top end cell equals cell open parentheses table row cell straight x subscript straight B minus straight x subscript straight A end cell row cell straight y subscript straight B minus straight y subscript straight A end cell row cell straight z subscript straight B minus straight z subscript straight A end cell end table close parentheses equals open parentheses table row cell negative 1 minus 2 end cell row cell 4 minus open parentheses negative 1 close parentheses end cell row cell negative 2 minus open parentheses negative 1 close parentheses end cell end table close parentheses equals open parentheses table row cell negative 3 end cell row 5 row cell negative 1 end cell end table close parentheses end cell row cell AC with rightwards arrow on top end cell equals cell open parentheses table row cell straight x subscript straight C minus straight x subscript straight A end cell row cell straight y subscript straight C minus straight y subscript straight A end cell row cell straight z subscript straight C minus straight z subscript straight A end cell end table close parentheses equals open parentheses table row cell 5 minus 2 end cell row cell 0 minus open parentheses negative 1 close parentheses end cell row cell negative 3 minus open parentheses negative 1 close parentheses end cell end table close parentheses equals open parentheses table row 3 row 1 row cell negative 2 end cell end table close parentheses end cell end table end style

Kemudian,

table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px AB with size 14px rightwards arrow on top size 14px times size 14px AC with size 14px rightwards arrow on top end cell size 14px equals cell begin mathsize 14px style open parentheses table row cell negative 3 end cell row 5 row cell negative 1 end cell end table close parentheses end style size 14px times begin mathsize 14px style open parentheses table row 3 row 1 row cell negative 2 end cell end table close parentheses end style end cell row blank size 14px equals cell begin mathsize 14px style left parenthesis negative 3 right parenthesis end style size 14px times size 14px 3 size 14px plus size 14px 5 size 14px times size 14px 1 size 14px plus begin mathsize 14px style left parenthesis negative 1 right parenthesis end style size 14px times begin mathsize 14px style left parenthesis negative 2 right parenthesis end style end cell row blank size 14px equals cell size 14px minus size 14px 9 size 14px plus size 14px 5 size 14px plus size 14px 2 end cell row blank size 14px equals cell size 14px minus size 14px 2 end cell row cell begin mathsize 14px style vertical line AC with rightwards arrow on top vertical line end style end cell size 14px equals cell square root of size 14px 3 to the power of size 14px 2 size 14px plus size 14px 1 to the power of size 14px 2 size 14px plus begin mathsize 14px style left parenthesis negative 2 right parenthesis end style to the power of size 14px 2 end root end cell row blank size 14px equals cell square root of size 14px 9 size 14px plus size 14px 1 size 14px plus size 14px 4 end root end cell row blank size 14px equals cell square root of size 14px 14 end cell end table  

Maka proyeksi vektor undefined pada undefined adalah

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator AB with rightwards arrow on top times AC with rightwards arrow on top blank over denominator open vertical bar AC with rightwards arrow on top close vertical bar squared end fraction close parentheses AC with rightwards arrow on top end cell equals cell open parentheses fraction numerator negative 2 over denominator open parentheses square root of 14 close parentheses squared end fraction close parentheses open parentheses table row 3 row 1 row cell negative 2 end cell end table close parentheses end cell row blank equals cell negative 2 over 14 open parentheses table row 3 row 1 row cell negative 2 end cell end table close parentheses end cell row blank equals cell negative 1 over 7 open parentheses table row 3 row 1 row cell negative 2 end cell end table close parentheses end cell row blank equals cell negative 1 over 7 open parentheses 3 straight i with hat on top plus straight j with hat on top minus 2 straight k with hat on top close parentheses end cell end table end style 

Jadi, jawaban yang tepat adalah C.space space  

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