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Diketahui konstanta ionisasi asam asetat , pH 100 ...

Diketahui konstanta ionisasi asam asetat begin mathsize 14px style equals 1 comma 8 cross times 10 to the power of negative sign 5 end exponent end style, pH 100 mL larutan begin mathsize 14px style Ca open parentheses C H subscript 3 C O O close parentheses subscript 2 end style 1 M adalah ...

  1. begin mathsize 14px style 4 minus sign log space 3 end style 

  2. begin mathsize 14px style 4 plus log space 3 end style  

  3. begin mathsize 14px style 9 minus sign log space 3 end style  

  4. begin mathsize 14px style 9 plus log space 3 end style 

  5. begin mathsize 14px style 10 minus sign log space 3 end style 

Jawaban:

Hitung konsentrasi anion garam menggunakan perbandingan koefisien,

begin mathsize 14px style Ca open parentheses C H subscript 3 C O O close parentheses subscript 2 yields Ca to the power of 2 plus sign plus space 2 C H subscript 3 C O O to the power of minus sign space space space space space left parenthesis 1 M space space right parenthesis space space space space space space space space space space space space space left parenthesis 1 M space right parenthesis space space space space space space space space left parenthesis space 2 M right parenthesis end style 

begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets equals square root of K subscript w over K subscript a middle dot open square brackets garam close square brackets end root space space space space space space space space space equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 1 comma 8 cross times 10 to the power of negative sign 5 end exponent end fraction middle dot 2 end root space space space space space space space space space equals square root of fraction numerator 10 to the power of negative sign 9 end exponent over denominator 1 comma 8 end fraction middle dot 2 space end root space space space space space space space space space equals square root of 1 comma 1 middle dot 10 to the power of negative sign 9 end exponent end root space space space space space space space space space equals square root of 11 cross times 10 to the power of negative sign 10 end exponent end root space space space space space space space space space equals 3 comma 3 cross times 10 to the power of negative sign 5 end exponent end style 

begin mathsize 14px style pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets space space space space space space space equals minus sign log space 3 comma 3 cross times 10 to the power of negative sign 5 end exponent space space space space space space space equals 5 minus sign log space 3 comma 3 pH equals 14 minus sign pOH space space space space space equals 14 minus sign left parenthesis 5 minus sign log space 3 comma 3 right parenthesis space space space space space equals 9 plus log space 3 comma 3 end style 

Jadi, pH larutan menjadi 9+log 3,3

 

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