Pertanyaan

Diketahui .Jika maka adalah ...

Diketahui $begin mathsize 14px style open parentheses g blank o blank f close parentheses open parentheses x close parentheses equals fraction numerator 10 x plus 6 over denominator 4 x plus 3 end fraction comma x not equal to negative 3 over 4 end style$ . Jika maka adalah ...

$begin mathsize 14px style fraction numerator 5 x minus 9 over denominator 2 x minus 3 end fraction comma x not equal to 3 over 2 end style$
$begin mathsize 14px style fraction numerator 5 x plus 1 over denominator 2 x minus 3 end fraction comma x not equal to 3 over 2 end style$
$begin mathsize 14px style fraction numerator 5 x plus 9 over denominator 2 x minus 1 end fraction comma x not equal to 1 half end style$
$begin mathsize 14px style fraction numerator 2 x plus 1 over denominator 2 x minus 3 end fraction comma x not equal to 3 over 2 end style$
$begin mathsize 14px style fraction numerator 2 x plus 1 over denominator 2 x minus 1 end fraction comma x not equal to 1 half end style$

H. Firmansyah

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

Pembahasan

Diketahui: Ditanyakan: Jawab: Misal: maka, Dengan mensubstitusikan x = a maka diperoleh Jadi, jawaban yang tepat adalah A.

Diketahui:

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g blank o blank f close parentheses open parentheses x close parentheses end cell equals cell fraction numerator 10 x plus 6 over denominator 4 x plus 3 end fraction end cell row cell f open parentheses x close parentheses end cell equals cell 2 x plus 3 end cell end table end style$

Ditanyakan:

Jawab:

Misal:

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 2 x plus 3 end cell equals cell a space end cell row cell 2 x end cell equals cell a minus 3 end cell row x equals cell fraction numerator a minus 3 over denominator 2 end fraction end cell end table end style$

maka,

$table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g blank o blank f close parentheses open parentheses x close parentheses end cell equals cell fraction numerator 10 x plus 6 over denominator 4 x plus 3 end fraction end cell row cell g open parentheses f open parentheses x close parentheses close parentheses end cell equals cell fraction numerator 10 x plus 6 over denominator 4 x plus 3 end fraction end cell row cell g open parentheses 2 x plus 3 close parentheses end cell equals cell fraction numerator 10 x plus 6 over denominator 4 x plus 3 end fraction end cell row cell g open parentheses a close parentheses end cell equals cell fraction numerator 10 open parentheses fraction numerator a minus 3 over denominator 2 end fraction close parentheses plus 6 over denominator 4 open parentheses fraction numerator a minus 3 over denominator 2 end fraction close parentheses plus 3 end fraction end cell row cell g open parentheses a close parentheses end cell equals cell fraction numerator 5 a minus 9 over denominator 2 a minus 3 end fraction end cell end table$

Dengan mensubstitusikan $x = a$ maka diperoleh

$table attributes columnalign right center left columnspacing 0px end attributes row cell g open parentheses x close parentheses end cell equals cell fraction numerator 5 x minus 9 over denominator 2 x minus 3 end fraction comma blank x not equal to 3 over 2 end cell end table$

Jadi, jawaban yang tepat adalah A.