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Diketahui fungsi f:R→R dan g:R→R. Jika fungsi  f(x)=3x−52x+7​, x=35​ dan g−1(x)=4x−1, Nilai fungsi  (f∘g)−1(2)adalah ...

Pertanyaan

Diketahui fungsi begin mathsize 14px style f colon R rightwards arrow R end style dan begin mathsize 14px style g colon R rightwards arrow R end style. Jika fungsi  begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x plus 7 over denominator 3 x minus 5 end fraction comma space x not equal to 5 over 3 end style dan begin mathsize 14px style g to the power of negative 1 end exponent left parenthesis x right parenthesis equals 4 x minus 1 end style, Nilai fungsi  begin mathsize 14px style left parenthesis f ring operator g right parenthesis to the power of negative 1 end exponent open parentheses 2 close parentheses end styleadalah ... 

  1. begin mathsize 14px style negative 8 end style 

  2. begin mathsize 14px style 8 end style 

  3. begin mathsize 14px style 10 end style 

  4. begin mathsize 14px style 12 end style 

  5. begin mathsize 14px style 16 end style 

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Jawaban

jawaban yang tepat  adalah E

Pembahasan

Pertama akan dicari invers dari fungsi  begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x plus 7 over denominator 3 x minus 5 end fraction comma space x not equal to 5 over 3 end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row y equals cell fraction numerator 2 x plus 7 over denominator 3 x minus 5 end fraction end cell row cell 3 y x minus 5 y end cell equals cell 2 x plus 7 end cell row cell 3 y x minus 2 x end cell equals cell 5 y plus 7 end cell row cell x open parentheses 3 y minus 2 close parentheses end cell equals cell 5 y plus 7 end cell row x equals cell fraction numerator 5 y plus 7 over denominator 3 y minus 2 end fraction end cell row cell f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator 5 x plus 7 over denominator 3 x minus 2 end fraction end cell end table end style 

Dengan menggunakan sifat invers akan ditentukan  begin mathsize 14px style left parenthesis f ring operator g right parenthesis to the power of negative 1 end exponent open parentheses x close parentheses end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses f ring operator g close parentheses to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell open parentheses g to the power of negative 1 end exponent ring operator f to the power of negative 1 end exponent close parentheses open parentheses x close parentheses end cell row cell space space space space space space space space space space space space space space space space end cell equals cell g to the power of negative 1 end exponent open parentheses fraction numerator 5 x plus 7 over denominator 3 x minus 2 end fraction close parentheses end cell row cell space space space space space space space space space space space space space space space space end cell equals cell 4 open parentheses fraction numerator 5 x plus 7 over denominator 3 x minus 2 end fraction close parentheses minus 1 end cell row cell space space space space space space space space space space space space space space space space end cell equals cell fraction numerator 20 x plus 28 minus 3 x plus 2 over denominator 3 x minus 2 end fraction end cell row cell space space space space space space space space space space space space space space space space end cell equals cell fraction numerator 17 x plus 30 over denominator 3 x minus 2 end fraction end cell end table end style        

Nilai fugsi begin mathsize 14px style left parenthesis f ring operator g right parenthesis to the power of negative 1 end exponent open parentheses 2 close parentheses end style adalah  

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis f ring operator g right parenthesis to the power of negative 1 end exponent open parentheses 2 close parentheses end cell equals cell fraction numerator 17 open parentheses 2 close parentheses plus 30 over denominator 3 open parentheses 2 close parentheses minus 2 end fraction end cell row cell space space space space space space space space space space space space space space space space space end cell equals cell fraction numerator 34 plus 30 over denominator 6 minus 2 end fraction end cell row cell space space space space space space space space space space space space space space space space space end cell equals cell 64 over 4 end cell row cell space space space space space space space space space space space space space space space space space end cell equals 16 end table end style  

Jadi, jawaban yang tepat  adalah E

289

4.6 (24 rating)

Aulia Putri Kusumaningrum

Pembahasan lengkap banget Ini yang aku cari! Mudah dimengerti Bantu banget Makasih ❤️

Nabil Zahra Aldenda

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VANYA TAFDHILATUN NISA

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Pertanyaan serupa

Diketahui fungsi f:R→R dengan g:R→R masing-masing ditentukan dengan f(x)=x+5 dan g(x)=3x+2. Tentukan: b. (g∘f)−1(x)

21

4.0

Jawaban terverifikasi

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