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Diketahui f ( x ) = 3 x + 1 ⋅ 6 x − 3 dan g ( x ) = 1 8 x − 2 dimana x ∈ bilangan asli . Tentukan g ( x ) f ( x ) ​ !

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S. Yoga

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

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hasil dari adalah .

hasil dari fraction numerator f left parenthesis x right parenthesis over denominator g left parenthesis x right parenthesis end fraction adalah 9 over 2.

Pembahasan

Diketahui: dimana Mencari : Jadi, hasil dari adalah .

Diketahui:

f left parenthesis x right parenthesis equals 3 to the power of x plus 1 end exponent times 6 to the power of x minus 3 end exponent space dan space g left parenthesis x right parenthesis equals 18 to the power of x minus 2 end exponent dimana x element of bilangan space asli

Mencari fraction numerator f left parenthesis x right parenthesis over denominator g left parenthesis x right parenthesis end fraction:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator f left parenthesis x right parenthesis over denominator g left parenthesis x right parenthesis end fraction end cell equals cell fraction numerator 3 to the power of x plus 1 end exponent times thin space 6 to the power of x minus 3 end exponent over denominator 18 to the power of x minus 2 end exponent end fraction end cell row blank equals cell fraction numerator 3 to the power of x plus 1 end exponent times thin space 6 to the power of x minus 3 end exponent over denominator 3 to the power of 2 open parentheses x minus 2 close parentheses end exponent times thin space 2 to the power of x minus 2 end exponent end fraction end cell row blank equals cell fraction numerator 3 to the power of negative x plus 5 end exponent times thin space 6 to the power of x minus 3 end exponent over denominator 2 to the power of x minus 2 end exponent end fraction end cell row blank equals cell fraction numerator 3 to the power of negative x plus 5 end exponent times thin space 2 to the power of x minus 3 end exponent times thin space 3 to the power of x minus 3 end exponent over denominator 2 to the power of x minus 2 end exponent end fraction end cell row blank equals cell 3 to the power of negative x plus 5 end exponent times thin space 2 to the power of negative 1 end exponent times thin space 3 to the power of x minus 3 end exponent end cell row blank equals cell 9 over 2 end cell end table 

Jadi, hasil dari fraction numerator f left parenthesis x right parenthesis over denominator g left parenthesis x right parenthesis end fraction adalah 9 over 2.

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