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Diketahui x = 2 ​ sin α + 7 ​ sin β y = 2 ​ cos α + 7 ​ cos β Diketahui pula nilai minimum dan maksimum dari x 2 + y 2 berturut-turut adalah a + b 14 ​ dan c + d 14 ​ , maka c + d a + b ​ = ....

Diketahui

Diketahui pula nilai minimum dan maksimum dari  berturut-turut adalah  dan , maka ....

  1. begin mathsize 14px style negative 11 over 7 end style  

  2. size 14px 11 over size 14px 7  

  3. 1

  4. size 14px 7 over size 14px 11  

  5. size 14px minus size 14px 7 over size 14px 11  

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K. Putri

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Ganesha

Jawaban terverifikasi

Pembahasan

Perhatikan bahwa Perhatikan bahwa fungsi cosinus memiliki range di antara -1 dan 1. Sehingga Nilai minimum dari adalah Maka dan Nilai maksimum dari adalah Maka dan Dengan demikian, Jadi, jawaban yang tepat adalah D.

Perhatikan bahwa

begin mathsize 12px style table attributes columnalign right center left columnspacing 0px end attributes row cell x squared plus y squared end cell equals cell left parenthesis square root of 2 s i n invisible function application alpha plus square root of 7 s i n invisible function application beta right parenthesis squared plus left parenthesis square root of 2 c o s invisible function application alpha plus square root of 7 c o s invisible function application beta right parenthesis end cell row blank equals cell left parenthesis 2 s i n squared invisible function application alpha plus 2 square root of 14 s i n invisible function application alpha space s i n invisible function application beta plus 7 s i n squared invisible function application beta right parenthesis end cell row blank blank cell plus left parenthesis 2 c o s squared invisible function application alpha plus 2 square root of 14 c o s invisible function application alpha c o s invisible function application beta plus 7 c o s squared invisible function application beta right parenthesis end cell row blank equals cell 2 s i n squared invisible function application alpha plus 2 c o s squared invisible function application alpha plus 2 square root of 14 space s i n invisible function application alpha space s i n invisible function application beta end cell row blank blank cell plus 2 square root of 14 space c o s invisible function application alpha space c o s invisible function application beta plus 7 s i n squared invisible function application beta plus 7 c o s squared invisible function application beta end cell row blank equals cell 2 left parenthesis s i n squared invisible function application alpha plus c o s squared invisible function application alpha right parenthesis end cell row blank blank cell plus 2 square root of 14 left parenthesis s i n invisible function application alpha space s i n invisible function application beta plus c o s invisible function application alpha space c o s invisible function application beta right parenthesis plus 7 left parenthesis s i n squared invisible function application beta plus 7 c o s squared invisible function application beta right parenthesis end cell row blank equals cell 2 left parenthesis 1 right parenthesis plus 2 square root of 14 left parenthesis c o s invisible function application alpha space c o s invisible function application beta plus s i n invisible function application alpha space s i n invisible function application beta right parenthesis plus 7 left parenthesis 1 right parenthesis end cell row blank equals cell 2 plus 2 square root of 14 space c o s invisible function application left parenthesis alpha minus beta right parenthesis plus 7 end cell row blank equals cell 9 plus 2 square root of 14 space c o s invisible function application left parenthesis alpha minus beta right parenthesis end cell end table end style 

Perhatikan bahwa fungsi cosinus memiliki range di antara -1 dan 1. Sehingga

begin mathsize 14px style table attributes columnspacing 0px 0px rowspacing 0px 0.25em end attributes row cell negative 1 less or equal than end cell cell cos open parentheses alpha minus beta close parentheses end cell cell less or equal than 1 end cell row cell negative 2 square root of 14 less or equal than end cell cell 2 square root of 14 cos open parentheses alpha minus beta close parentheses end cell cell less or equal than 2 square root of 14 end cell row cell 9 minus 2 square root of 14 less or equal than end cell cell 9 plus 2 square root of 14 cos open parentheses alpha minus beta close parentheses end cell cell less or equal than 9 plus 2 square root of 14 end cell row cell 9 minus 2 square root of 14 less or equal than end cell cell x squared plus y squared end cell cell less or equal than 9 plus 2 square root of 14 end cell end table end style

Nilai minimum dari begin mathsize 14px style x squared plus y squared end style adalah begin mathsize 14px style 9 minus 2 square root of 14. end style Maka begin mathsize 14px style a equals 9 end style dan size 14px b size 14px equals size 14px minus size 14px 2 size 14px.

Nilai maksimum dari begin mathsize 14px style x squared plus y squared end style adalah undefined Maka begin mathsize 14px style c equals 9 end style dan size 14px d size 14px equals size 14px 2 size 14px.

Dengan demikian, begin mathsize 14px style fraction numerator a plus b over denominator c plus d end fraction equals fraction numerator 9 plus left parenthesis negative 2 right parenthesis over denominator 9 plus 2 end fraction equals 7 over 11. end style

Jadi, jawaban yang tepat adalah D.
 

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