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Diketahui f ( x ) = 2 x − 1 dan g ( x ) = 3 x 2 + 4 . Tentukan: b. ( g ∘ f ) ( x ) d. ( g ∘ f ) ( − 1 )

Diketahui  dan . Tentukan:

b.  

d.   

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diperoleh dan

diperoleh begin mathsize 14px style bold left parenthesis bold italic g bold ring operator bold italic f bold right parenthesis bold left parenthesis bold italic x bold right parenthesis bold equals bold 12 bold italic x to the power of bold 2 bold minus bold 12 bold italic x bold plus bold 7 bold space end styledan begin mathsize 14px style bold left parenthesis bold italic g bold ring operator bold italic f bold right parenthesis bold left parenthesis bold minus bold 1 bold right parenthesis bold equals bold 21 bold space bold space end style    

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b. d. Jadi, diperoleh dan

b.  begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g ring operator f close parentheses open parentheses x close parentheses end cell equals cell g open parentheses f open parentheses x close parentheses close parentheses end cell row blank equals cell g open parentheses 2 x minus 1 close parentheses end cell row blank equals cell 3 open parentheses 2 x minus 1 close parentheses squared plus 4 end cell row blank equals cell 3 open parentheses 4 x squared minus 4 x plus 1 close parentheses plus 4 end cell row blank equals cell 12 x squared minus 12 x plus 3 plus 4 end cell row blank equals cell 12 x squared minus 12 x plus 7 end cell end table end style 

 

d. begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g ring operator f close parentheses open parentheses negative 1 close parentheses end cell equals cell 12 open parentheses negative 1 close parentheses squared minus 12 open parentheses negative 1 close parentheses plus 7 end cell row blank equals cell 12 plus 12 plus 7 end cell row blank equals 21 end table end style 

Jadi, diperoleh begin mathsize 14px style bold left parenthesis bold italic g bold ring operator bold italic f bold right parenthesis bold left parenthesis bold italic x bold right parenthesis bold equals bold 12 bold italic x to the power of bold 2 bold minus bold 12 bold italic x bold plus bold 7 bold space end styledan begin mathsize 14px style bold left parenthesis bold italic g bold ring operator bold italic f bold right parenthesis bold left parenthesis bold minus bold 1 bold right parenthesis bold equals bold 21 bold space bold space end style    

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Misal f ( x ) = 2 x − 3 x ​ dan g ( x ) = x 2 − 5 . Jika ( g ∘ f ) ( a ) = − 1 , tentukan nilai .

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