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Diketahui p ​ = 3 u + 2 v − w , q ​ = 5 u + a v − 5 w , dan r = 2 u − 2 v + b w secara berturut-turut menyatakan vektor posisi titik P, Q, dan R terhadap titik O. Jika titik P, Q, dan R terletak segaris, maka ab= ....

Diketahui , , dan secara berturut-turut menyatakan vektor posisi titik P, Q, dan R terhadap titik O. Jika titik P, Q, dan R terletak segaris, maka ab= ....

  1. - 10

  2. begin mathsize 14px style negative 2 over 5 end style

  3. 0

  4. begin mathsize 14px style 2 over 5 end style

  5. 10

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Pembahasan

Karena P, Q, dan R segaris, maka terdapat konstanta k sedemikian sehingga Perhatikan bahwa dan Kemudian cari konstanta k sehingga Maka didapatkan bahwa Sehingga Kemudian dan Sehinga

Karena P, Q, dan R segaris, maka terdapat konstanta k sedemikian sehingga

begin mathsize 14px style stack P Q with rightwards arrow on top equals k times stack Q R with rightwards arrow on top end style

Perhatikan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell stack P Q with rightwards arrow on top end cell equals cell stack O Q with rightwards arrow on top minus stack O P with rightwards arrow on top end cell row blank equals cell q with rightwards arrow on top minus p with rightwards arrow on top end cell row blank equals cell open parentheses 5 u with rightwards arrow on top plus a v with rightwards arrow on top minus 5 w with rightwards arrow on top close parentheses minus open parentheses 3 u with rightwards arrow on top plus 2 v with rightwards arrow on top minus w with rightwards arrow on top close parentheses end cell row blank equals cell 5 u with rightwards arrow on top plus a v with rightwards arrow on top minus 5 w with rightwards arrow on top minus 3 u with rightwards arrow on top minus 2 v with rightwards arrow on top plus w with rightwards arrow on top end cell row blank equals cell 2 u with rightwards arrow on top plus open parentheses a minus 2 close parentheses v with rightwards arrow on top minus 4 w with rightwards arrow on top end cell end table end style

dan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell stack Q R with rightwards arrow on top end cell equals cell stack O R with rightwards arrow on top minus stack O Q with rightwards arrow on top end cell row blank equals cell r with rightwards arrow on top minus q with rightwards arrow on top end cell row blank equals cell open parentheses 2 u with rightwards arrow on top minus 2 v with rightwards arrow on top plus b w with rightwards arrow on top close parentheses minus open parentheses 5 u with rightwards arrow on top plus a v with rightwards arrow on top minus 5 w with rightwards arrow on top close parentheses end cell row blank equals cell 2 u with rightwards arrow on top minus 2 v with rightwards arrow on top plus b w with rightwards arrow on top minus 5 u with rightwards arrow on top minus a v with rightwards arrow on top plus 5 w with rightwards arrow on top end cell row blank equals cell negative 3 u with rightwards arrow on top minus open parentheses 2 plus a close parentheses v with rightwards arrow on top plus open parentheses b plus 5 close parentheses w with rightwards arrow on top end cell end table end style

Kemudian cari konstanta k sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell stack P Q with rightwards arrow on top end cell equals cell k times stack Q R with rightwards arrow on top end cell row cell 2 u with rightwards arrow on top plus open parentheses a minus 2 close parentheses v with rightwards arrow on top minus 4 w with rightwards arrow on top end cell equals cell k open parentheses negative 3 u with rightwards arrow on top minus open parentheses 2 plus a close parentheses v with rightwards arrow on top plus open parentheses b plus 5 close parentheses w with rightwards arrow on top close parentheses end cell row cell 2 u with rightwards arrow on top plus open parentheses a minus 2 close parentheses v with rightwards arrow on top minus 4 w with rightwards arrow on top end cell equals cell negative 3 k u with rightwards arrow on top minus open parentheses 2 plus a close parentheses k v with rightwards arrow on top plus open parentheses b plus 5 close parentheses k w with rightwards arrow on top end cell end table end style

Maka didapatkan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row 2 equals cell negative 3 k end cell row cell a minus 2 end cell equals cell negative open parentheses 2 plus a close parentheses k end cell row cell negative 4 end cell equals cell open parentheses b plus 5 close parentheses k end cell end table end style

Sehingga

begin mathsize 14px style 2 equals negative 3 k space k equals negative 2 over 3 end style

Kemudian

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell a minus 2 end cell equals cell negative open parentheses 2 plus a close parentheses k end cell row cell a minus 2 end cell equals cell negative open parentheses 2 plus a close parentheses open parentheses negative 2 over 3 close parentheses end cell row cell a minus 2 end cell equals cell 4 over 3 plus 2 over 3 a end cell row cell a minus 2 over 3 a end cell equals cell 4 over 3 plus 2 end cell row cell 1 third a end cell equals cell 10 over 3 end cell row a equals 10 end table end style

dan

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell negative 4 end cell equals cell open parentheses b plus 5 close parentheses k end cell row cell negative 4 end cell equals cell open parentheses b plus 5 close parentheses open parentheses negative 2 over 3 close parentheses end cell row cell negative 4 open parentheses negative 3 over 2 close parentheses end cell equals cell b plus 5 end cell row 6 equals cell b plus 5 end cell row b equals 1 end table end style

Sehinga

begin mathsize 14px style a b equals 10 open parentheses 1 close parentheses equals 10 end style

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Perhatikan gambar berikut ini Diketahui titik C merupakan titik tengah OB. Jika OB = p ​ , A B = q ​ , dan AC diperpanjang hingga D dengan AC : CD = 5 : 2, maka B D = ...

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