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Pertanyaan

Diberikan kesamaan matriks open parentheses table row 5 1 row cell negative 3 end cell 2 end table close parentheses open parentheses table row 1 4 row cell negative 2 end cell 6 end table close parentheses equals 2 open parentheses table row cell negative 3 end cell cell 1 minus d end cell row cell c minus b end cell cell negative 5 end cell end table close parentheses plus open parentheses table row cell a plus 1 end cell 0 row 1 cell b plus a end cell end table close parentheses. Nilai a plus b plus c plus d equals...

  1. 6

  2. 2

  3. negative 5

  4. negative 8

  5. negative 9

N. Puspita

Master Teacher

Jawaban terverifikasi

Pembahasan

Ingat kembali:

Perkalian matriks dengan skalar

A equals open square brackets table row a b row c d end table close square brackets rightwards double arrow m A equals open square brackets table row cell m a end cell cell m b end cell row cell m c end cell cell m d end cell end table close square brackets

Penjumlahan dua matriks:

A equals open square brackets table row a b row c d end table close square brackets comma space B equals open square brackets table row e f row g h end table close square brackets space rightwards double arrow A plus B equals open square brackets table row cell a plus e end cell cell b plus f end cell row cell c plus g end cell cell d plus h end cell end table close square brackets

Perkalian dua matriks:

A equals open square brackets table row a b row c d end table close square brackets comma space B equals open square brackets table row e f row g h end table close square brackets space rightwards double arrow A plus B equals open square brackets table row cell a e plus b g end cell cell a f plus b h end cell row cell c e plus d g end cell cell c f plus d h end cell end table close square brackets

Sehingga diperoleh perhitungan:

begin mathsize 12px style open parentheses table row 5 1 row cell negative 3 end cell 2 end table close parentheses open parentheses table row 1 4 row cell negative 2 end cell 6 end table close parentheses equals 2 open parentheses table row cell negative 3 end cell cell 1 minus d end cell row cell c minus b end cell cell negative 5 end cell end table close parentheses plus open parentheses table row cell a plus 1 end cell 0 row 1 cell b plus a end cell end table close parentheses open parentheses table row cell 5 minus 2 end cell cell 20 plus 6 end cell row cell negative 3 plus open parentheses negative 4 close parentheses end cell cell negative 12 plus 12 end cell end table close parentheses equals open parentheses table row cell negative 6 end cell cell 2 minus 2 d end cell row cell 2 c minus 2 b end cell cell negative 10 end cell end table close parentheses plus open parentheses table row cell a plus 1 end cell 0 row 1 cell b plus a end cell end table close parentheses open parentheses table row 3 26 row cell negative 7 end cell 0 end table close parentheses equals open parentheses table row cell negative 6 plus a plus 1 end cell cell 2 minus 2 d end cell row cell 2 c minus 2 b plus 1 end cell cell negative 10 plus b plus a end cell end table close parentheses open parentheses table row 3 26 row cell negative 7 end cell 0 end table close parentheses equals open parentheses table row cell a minus 5 end cell cell 2 minus 2 d end cell row cell 2 c minus 2 b plus 1 end cell cell negative 10 plus b plus a end cell end table close parentheses end style 

Sehingga dari kesamaan di atas diperoleh persamaan:

table attributes columnalign right center left columnspacing 0px end attributes row 3 equals cell a minus 5 end cell row a equals cell 3 plus 5 end cell row a equals cell 8... open parentheses 1 close parentheses end cell row blank blank blank row 26 equals cell 2 minus 2 d end cell row cell 2 d end cell equals cell 2 minus 26 end cell row d equals cell fraction numerator negative 24 over denominator 2 end fraction end cell row d equals cell negative 12...... open parentheses 2 close parentheses end cell row blank blank blank row 0 equals cell negative 10 plus b plus a end cell row 10 equals cell b plus open parentheses 8 close parentheses end cell row b equals cell 10 minus 8 end cell row b equals cell 2......... open parentheses 3 close parentheses end cell row blank blank blank row cell negative 7 end cell equals cell 2 c minus 2 b plus 1 end cell row cell 2 c minus 2 open parentheses 2 close parentheses end cell equals cell negative 7 minus 1 end cell row cell 2 c minus 4 end cell equals cell negative 8 end cell row cell 2 c end cell equals cell negative 4 end cell row c equals cell fraction numerator negative 4 over denominator 2 end fraction end cell row c equals cell negative 2.......... open parentheses 4 close parentheses end cell end table  

Sehingga,

table attributes columnalign right center left columnspacing 0px end attributes row cell a plus b plus c plus d end cell equals cell 8 plus 2 plus open parentheses negative 2 close parentheses plus open parentheses negative 12 close parentheses end cell row blank equals cell negative 4 end cell end table

Dengan demikian, hasil dari table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank b end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank c end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table adalah negative 4

Jadi, tidak ada jawaban yang tepat

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