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dan  adalah akar-akar persamaan , nilai

Pertanyaan

alpha dan beta adalah akar-akar persamaan open parentheses 1 over 9 close parentheses to the power of x squared minus 4 x plus 7 end exponent equals open parentheses 27 close parentheses cross times 3 to the power of x squared minus 4 x plus 4 end exponent, nilai alpha beta equals...

  1. negative 7

  2. negative 4

  3. negative 2

  4. 4

  5. 7 

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 1 over 9 close parentheses to the power of x squared minus 4 x plus 7 end exponent end cell equals cell open parentheses 27 close parentheses cross times 3 to the power of x squared minus 4 x plus 4 end exponent end cell row cell open parentheses 3 to the power of negative 2 end exponent close parentheses to the power of x squared minus 4 x plus 7 end exponent end cell equals cell 3 cubed cross times 3 to the power of x squared minus 4 x plus 4 end exponent end cell row cell up diagonal strike 3 to the power of negative 2 x squared plus 8 x minus 14 end exponent end cell equals cell up diagonal strike 3 to the power of x squared minus 4 x plus 7 end exponent end cell row cell negative 2 x squared plus 8 x minus 14 end cell equals cell x squared minus 4 x plus 7 end cell row cell 3 x squared minus 12 x plus 21 end cell equals 0 row cell x squared minus 4 x plus 7 end cell equals 0 row blank blank blank row cell alpha times beta end cell equals cell c over a equals 7 over 1 equals 7 end cell end table

Jadi, jawaban yang tepat adalah E.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 19 Mei 2021

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